help with gcc 3.1 error message

[ken]

I cannot see how I am getting this error message:

TreeAddress aResult( memory::Pointer (aBaseAddress) );

if (TreeFragment * pFragment = TreeAccessor::a ccess(aResult,_ anUpdater))


/data2/office/configmgr/source/tree/builddata.cxx: In member function
`configmgr ::data::TreeAdd ress configmgr::data ::TreeNodeBuild er::
allocTreeFragme nt(configmg r::memory::Upda teAccessor&)':
/data2/office/configmgr/source/tree/builddata.cxx:6 58: error: no matching
function for
call to `configmgr::dat a::TreeAccessor ::access(config mgr::data::Tree Address (&)
(configmgr::mem ory::Pointer), configmgr::memo ry::UpdateAcces sor&)'
.../inc/treeaccessor.hx x:139: error: candidates are
: static configmgr::shar able:: TreeFragment*
configmgr::data ::TreeAccessor: :
access(const configmgr::data ::TreeA ddress&,
configmgr::memo ry::UpdateAcces sor&)
.../inc/treeaccessor.hx x:141: error: static const configmgr::shar
able::TreeFragm ent*
configmgr::data ::TreeAccessor: :access(const configmgr::data :
:TreeAddress&,
const configmgr::memo ry::Accessor&)

[Rob Williscroft]

Re: help with gcc 3.1 error message

ken wrote in news:pan.2003.0 7.20.12.38.59.9 8859@gandalf.fo skey.org:
[color=blue]
> I cannot see how I am getting this error message:
>
> TreeAddress aResult( memory::Pointer (aBaseAddress) );[/color]

The above is a function declaration ie:

TreeAddress aResult( memory::Pointer aBaseAddress );

change it to:

TreeAddress aResult = memory::Pointer (aBaseAddress);

or maybe:

TreeAddress aResult( ( memory::Pointer (aBaseAddress) ) );

[color=blue]
>
> if (TreeFragment * pFragment =
> TreeAccessor::a ccess(aResult,_ anUpdater))
>
>
> /data2/office/configmgr/source/tree/builddata.cxx: In member function
> `configmgr ::data::TreeAdd ress configmgr::data ::TreeNodeBuild er::
> allocTreeFragme nt(configmg r::memory::Upda teAccessor&)':
> /data2/office/configmgr/source/tree/builddata.cxx:6 58: error: no
> matching function for
> call to[/color]

This is the bit you needed to read carefully:
[color=blue]
> `configmgr::dat a::TreeAccessor ::access(config mgr::data::Tree Address
> (&) (configmgr::mem ory::Pointer), configmgr::memo ry::UpdateAcces sor&)'[/color]

Note the type of the first argument.
[color=blue]
> ../inc/treeaccessor.hx x:139: error: candidates are
> : static configmgr::shar able:: TreeFragment*
> configmgr::data ::TreeAccessor: :
> access(const configmgr::data ::TreeA ddress&,
> configmgr::memo ry::UpdateAcces sor&)
> ../inc/treeaccessor.hx x:141: error: static const configmgr::shar
> able::TreeFragm ent*
> configmgr::data ::TreeAccessor: :access(const configmgr::data :
> :TreeAddress&,
> const configmgr::memo ry::Accessor&)
>[/color]

HTH

Rob.
--

http://www.victim-prime.dsl.pipex.com/

[Michael Kochetkov]

Re: help with gcc 3.1 error message


"Rob Williscroft" <rtw@freenet.RE MOVE.co.uk> wrote in message
news:Xns93BE998 4B5530ukcoREMOV Efreenetrtw@195 .129.110.200...[color=blue]
> ken wrote in news:pan.2003.0 7.20.12.38.59.9 8859@gandalf.fo skey.org:
>[color=green]
> > I cannot see how I am getting this error message:
> >
> > TreeAddress aResult( memory::Pointer (aBaseAddress) );[/color]
>
> The above is a function declaration ie:
>
> TreeAddress aResult( memory::Pointer aBaseAddress );
>
> change it to:
>
> TreeAddress aResult = memory::Pointer (aBaseAddress);
>
> or maybe:
>
> TreeAddress aResult( ( memory::Pointer (aBaseAddress) ) );[/color]
No, it will not help. You might with to consider the proper static_cast
instead.

--
With regards,
Michael Kochetkov.

[ken]

Re: help with gcc 3.1 error message

On Sun, 20 Jul 2003 19:09:01 +0400, Michael Kochetkov wrote:
[color=blue]
>
> "Rob Williscroft" <rtw@freenet.RE MOVE.co.uk> wrote in message
> news:Xns93BE998 4B5530ukcoREMOV Efreenetrtw@195 .129.110.200...[color=green]
>> ken wrote in news:pan.2003.0 7.20.12.38.59.9 8859@gandalf.fo skey.org:
>>[color=darkred]
>> > I cannot see how I am getting this error message:
>> >
>> > TreeAddress aResult( memory::Pointer (aBaseAddress) );[/color]
>>
>> The above is a function declaration ie:
>>
>> TreeAddress aResult( memory::Pointer aBaseAddress );
>>
>> change it to:
>>
>> TreeAddress aResult = memory::Pointer (aBaseAddress);
>>
>> or maybe:
>>
>> TreeAddress aResult( ( memory::Pointer (aBaseAddress) ) );[/color]
> No, it will not help. You might with to consider the proper static_cast
> instead.[/color]

Static cast was the original code. It compiled fine until 3.3.1

TreeAddress aResult( static_cast<mem ory::Pointer>(a BaseAddress) );

Isn't memory::Pointer (aBaseAddress) instantiating a temporary of type
memory::Pointer , not declaring a variable ABaseAddress. The brackets
are calling the constructor.

I now understand how to work around this, I just don't understand what I did
wrong.

--
Ta
KenF

[John Harrison]

Re: help with gcc 3.1 error message


"ken" <ken@gandalf.fo skey.org> wrote in message
news:pan.2003.0 7.20.23.28.42.6 88129@gandalf.f oskey.org...[color=blue]
> On Sun, 20 Jul 2003 19:09:01 +0400, Michael Kochetkov wrote:
>[color=green]
> >
> > "Rob Williscroft" <rtw@freenet.RE MOVE.co.uk> wrote in message
> > news:Xns93BE998 4B5530ukcoREMOV Efreenetrtw@195 .129.110.200...[color=darkred]
> >> ken wrote in news:pan.2003.0 7.20.12.38.59.9 8859@gandalf.fo skey.org:
> >>
> >> > I cannot see how I am getting this error message:
> >> >
> >> > TreeAddress aResult( memory::Pointer (aBaseAddress) );
> >>
> >> The above is a function declaration ie:
> >>
> >> TreeAddress aResult( memory::Pointer aBaseAddress );
> >>
> >> change it to:
> >>
> >> TreeAddress aResult = memory::Pointer (aBaseAddress);
> >>
> >> or maybe:
> >>
> >> TreeAddress aResult( ( memory::Pointer (aBaseAddress) ) );[/color]
> > No, it will not help. You might with to consider the proper static_cast
> > instead.[/color]
>
> Static cast was the original code. It compiled fine until 3.3.1
>
> TreeAddress aResult( static_cast<mem ory::Pointer>(a BaseAddress) );
>
> Isn't memory::Pointer (aBaseAddress) instantiating a temporary of type
> memory::Pointer , not declaring a variable ABaseAddress. The brackets
> are calling the constructor.
>
> I now understand how to work around this, I just don't understand what I[/color]
did[color=blue]
> wrong.
>[/color]

No, memory::Pointer (aBaseAddress) is a parameter type, followed by a
parameter name. The brackets are ignored. I.e.

TreeAddress aResult( memory::Pointer (aBaseAddress) );

is exactly the same as

TreeAddress aResult( memory::Pointer aBaseAddress );

which is a function prototype.

There is a rule in C++, if something could be an expression or a
declaration, its treated as a declaration. See the recent thread 'Temporary
creation vs. variable declaration' for other examples.

john

[Michael Kochetkov]

Re: help with gcc 3.1 error message


"Rob Williscroft" <rtw@freenet.RE MOVE.co.uk> wrote in message
news:Xns93BEC7D 986EE9ukcoREMOV Efreenetrtw@195 .129.110.131...[color=blue]
> Michael Kochetkov wrote in news:3f1ab092$1 @news.trustwork s.com:
>[color=green]
> >
> > "Rob Williscroft" <rtw@freenet.RE MOVE.co.uk> wrote in message
> > news:Xns93BE998 4B5530ukcoREMOV Efreenetrtw@195 .129.110.200...[color=darkred]
> >> ken wrote in news:pan.2003.0 7.20.12.38.59.9 8859@gandalf.fo skey.org:
> >>
> >> > I cannot see how I am getting this error message:
> >> >
> >> > TreeAddress aResult( memory::Pointer (aBaseAddress) );
> >>
> >> The above is a function declaration ie:
> >>
> >> TreeAddress aResult( memory::Pointer aBaseAddress );
> >>
> >> change it to:
> >>
> >> TreeAddress aResult = memory::Pointer (aBaseAddress);
> >>
> >> or maybe:
> >>
> >> TreeAddress aResult( ( memory::Pointer (aBaseAddress) ) );[/color]
> > No, it will not help. You might with to consider the proper static_cast
> > instead.
> >[/color]
>
> Maybe, but if so, you and the OP have non-comforming compilers.[/color]
Right you are. I have overlooked the opening parenthesis place (I have
considered TreeAddress (aResult( memory::Pointer (aBaseAddress) ) ); ).
Sorry.

--
With regards,
Michael Kochetkov.

[ken]

Re: help with gcc 3.1 error message

On Mon, 21 Jul 2003 07:08:31 +0100, John Harrison wrote:
[color=blue]
> There is a rule in C++, if something could be an expression or a
> declaration, its treated as a declaration. See the recent thread 'Temporary
> creation vs. variable declaration' for other examples.[/color]

The penny drops, thanks for your help.

--
KenF