syntax problem

[muser]

I'am having problem with the following:

rec1len = strlen(temp1);

temp1 is a character array, multi dimensional array.
it has been initialised as char temp1[12][104];
int rec1len.
error for this message: C:\Program Files\Microsoft Visual
Studio\MyProjec ts\Valid\Zenith 124\Zenith.cpp( 162) : error C2664:
'strlen' : cannot convert parameter 1 from 'char [12][104]' to 'const
char *'

can anyone help please.

[MiniDisc_2k2]

Re: syntax problem


"muser" <charlie12345@h otmail.com> wrote in message
news:f9a2a258.0 307120516.29240 315@posting.goo gle.com...[color=blue]
> I'am having problem with the following:
>
> rec1len = strlen(temp1);
>
> temp1 is a character array, multi dimensional array.
> it has been initialised as char temp1[12][104];
> int rec1len.
> error for this message: C:\Program Files\Microsoft Visual
> Studio\MyProjec ts\Valid\Zenith 124\Zenith.cpp( 162) : error C2664:
> 'strlen' : cannot convert parameter 1 from 'char [12][104]' to 'const
> char *'
>
> can anyone help please.[/color]

That's not how strlen() works. strlen() works with char*s, not character
arrays.

If you had something like this:

char temp1[12];

It would work if you took the address of that:

rec1len = strlen(&temp1);

But because you have a multidimensiona l array, you cannot do that. What I'm
assuming you're doing is having 104 "strings" which are up to 12 characters
long (or 12 strings up to 104 characters long). Note I say string here
meaning the C style string, that is, a char*. Perfectly legal in C++ but a
little bit harder to work with. If you must keep it char[12][104] and just
wanted to add up all of the string lengths, here's what you'll want to do:

rec1len = 0;
for (int x = 0; x < 104; x++)
rec1len += strlen(&temp1[x]);

I'm pretty sure that's how it works. I may have the two indexes mixed up,
but you're only supposed to put one of them down. I think it's the second
one, and then take the address of the first. Anyone else there please feel
free to pipe in if I got it wrong.

BTW: In C++, we have an easier way of dealing with strings, the aptly named
string class. First off, you'll need to

#include <string>
using namespace std; // if you haven't already

string temp1[104]; // make 104 strings

And now to add up the lengths, you could

rec1len = 0;
for (int x = 0; x < 104; x++)
rec1len += temp1[x].length();


Code Not Compiled
--
MiniDisc_2k2

[Bob Jacobs]

Re: syntax problem

"muser" <charlie12345@h otmail.com> wrote in message
news:f9a2a258.0 307120516.29240 315@posting.goo gle.com...[color=blue]
> I'am having problem with the following:
>
> rec1len = strlen(temp1);
>
> temp1 is a character array,[/color]

It's an array of arrays in fact.
[color=blue]
> multi dimensional array.
> it has been initialised as char temp1[12][104];
> int rec1len.
> error for this message: C:\Program Files\Microsoft Visual
> Studio\MyProjec ts\Valid\Zenith 124\Zenith.cpp( 162) : error C2664:
> 'strlen' : cannot convert parameter 1 from 'char [12][104]' to 'const
> char *'
>
> can anyone help please.[/color]

What is it that you're intending with strlen(temp1)? It's not 100% clear to
me.

If you want string length, which string do you want the length of? You have
an array of strings so identify which one you want, for instance:

int rec1len = strlen(temp[0]);

for the first string, or:

int rec12len = strlen(temp[11]);

for the last string.

[John Carson]

Re: syntax problem

"muser" <charlie12345@h otmail.com> wrote in message
news:f9a2a258.0 307120516.29240 315@posting.goo gle.com[color=blue]
> I'am having problem with the following:
>
> rec1len = strlen(temp1);
>
> temp1 is a character array, multi dimensional array.
> it has been initialised as char temp1[12][104];
> int rec1len.
> error for this message: C:\Program Files\Microsoft Visual
> Studio\MyProjec ts\Valid\Zenith 124\Zenith.cpp( 162) : error C2664:
> 'strlen' : cannot convert parameter 1 from 'char [12][104]' to 'const
> char *'
>
> can anyone help please.[/color]

Not sure what you are trying to do. strlen is not meant to work with
multi-dimensional arrays. You can call

strlen(temp1[i])

to get the length of row i for any i = 0 to 11. But this will only work if
the row is nul terminated. strlen counts the number of characters before the
'\0' character is encountered.


--
John Carson
1. To reply to email address, remove donald
2. Don't reply to email address (post here instead)

[John Harrison]

Re: syntax problem


"muser" <charlie12345@h otmail.com> wrote in message
news:f9a2a258.0 307120516.29240 315@posting.goo gle.com...[color=blue]
> I'am having problem with the following:
>
> rec1len = strlen(temp1);
>
> temp1 is a character array, multi dimensional array.
> it has been initialised as char temp1[12][104];[/color]

declared as char temp1[12][104];, there's no initialisation going on there.
[color=blue]
> int rec1len.
> error for this message: C:\Program Files\Microsoft Visual
> Studio\MyProjec ts\Valid\Zenith 124\Zenith.cpp( 162) : error C2664:
> 'strlen' : cannot convert parameter 1 from 'char [12][104]' to 'const
> char *'
>
> can anyone help please.[/color]

What did you expect to happen? strlen is for strings, i.e. *one* dimensional
character arrays. If you explain what you are trying to do someone will be
able to help.

john