implicit vs. explicit type conversion for string vs. (char *)

[dmoos AT esigma-systems DOT de]

Hopefully somebody could teach me, what coding is correct,
clean and preferable:

#include <string>

int main(int argc, char **argv) {
std::string str = "lala";
char *cp = "lala";

return (cp == str) ? 0 : 1;
}

Is this code-snippet correct and ANSI-conform or should i
convert/copy/assign the content of cp into a string before
comparing to str?

All comments, hints and critics are highly appreciated.

Thanks in advance,

Darius.

[Ron Natalie]

Re: implicit vs. explicit type conversion for string vs. (char *)


"dmoos AT esigma-systems DOT de" <pfffffrrrrt@gm x.de> wrote in message news:bdegjr$s4b e3$1@ID-193014.news.dfn cis.de...
[color=blue]
> Is this code-snippet correct and ANSI-conform or should i
> convert/copy/assign the content of cp into a string before
> comparing to str?[/color]

There are operator== overloads in the standard library that
take combinations of string and char* and do the right thiing.

[Default User]

Re: implicit vs. explicit type conversion for string vs. (char *)



dmoos AT esigma-systems DOT de wrote:
[color=blue]
> #include <string>
>
> int main(int argc, char **argv) {
> std::string str = "lala";
> char *cp = "lala";
>
> return (cp == str) ? 0 : 1;
> }
>
> Is this code-snippet correct and ANSI-conform or should i
> convert/copy/assign the content of cp into a string before
> comparing to str?[/color]


Others have discussed the string comparison. I'll take this opportunity
to point out that returning anything from main() except for 0,
EXIT_SUCCESS or EXIT_FAILURE (inclusion of stdlib.h or cstdlib required
for the latter two) leads to implementation-specific results. For
maximum portability, don't return anything else (like 1) from main().




Brian Rodenborn