+ works for string literal also

[qazmlp]

int main()
{
std::string strVal = "2" ;
strVal = "000" + strVal ;
}

I am wondering how the above one compiles well. I expected that, it should be

int main()
{
std::string strVal = "2" ;
strVal = std::string("00 0") + strVal ;
}

[Ron Natalie]

Re: + works for string literal also


"qazmlp" <qazmlp1209@red iffmail.com> wrote in message news:db9bbf31.0 306242046.3d6d2 acb@posting.goo gle.com...[color=blue]
> int main()
> {
> std::string strVal = "2" ;
> strVal = "000" + strVal ;
> }
>
> I am wondering how the above one compiles well. I expected that, it should be
>[/color]
An overload for operator+ is provided
string operator+(const char*, const string& )

(Not literally, but the above is good enough to understand the issue).

This means you can mix most operations you can do with strings with char*'s pointing
at null terminated strings as long as one operand is a string type (obviously no overload
is possible if both args are pointers).

"000" + str;
str + "000"
str + str;

are all valid

"000" + "000"

is not.