passing argument to user defined type

[vivekian]

Hi,

trying to compile the following piece of code

class PeerList
{
public :
....
PeerList ( int noPieces )
{
// using noPieces to dynamically allocate memory for an
array.
}
~PeerList ()
{
....
}
};

Now trying to make a list of objects of type PeerList so trying the
following :

std::list <PeerList> pl ;

But , how is the argument -- 'int noPieces' to be passed to this
declaration ?

thanks in advance ,

[Asongala@gmail.com]

Re: passing argument to user defined type

std::list <PeerList> pl ;
PeerList p(int);
pl.push_back(p) ;

[andy@servocomm.freeserve.co.uk]

Re: passing argument to user defined type

Asongala@gmail. com wrote:[color=blue]
> std::list <PeerList> pl ;
> PeerList p(int);
> pl.push_back(p) ;[/color]

Or even :

std::list <PeerList> pl ;
PeerList p(1); // note Now this isnt a function definition!
pl.push_back(p) ;

//use Peerlist implicit int ctor
pl.push_back(42 );

cheers
Andy Little

[Marcus Kwok]

Re: passing argument to user defined type

andy@servocomm. freeserve.co.uk wrote:[color=blue]
> Or even :
>
> std::list <PeerList> pl ;
> PeerList p(1); // note Now this isnt a function definition!
> pl.push_back(p) ;
>
> //use Peerlist implicit int ctor
> pl.push_back(42 );[/color]

I would probably be explicit and do:

pl.push_back(Pe erList(42));

--
Marcus Kwok