pointer to function problem

[blackrosezy@gmail.com]

#include <cstdlib>
#include <iostream>

using namespace std;

int (*test)();
int (*test2)();

int aku(){

static int i = 0;
cout << "NO : " << i << endl;
i++;
}


int main()
{

test = &aku;
test2 = &aku;
(*test)();
(*test)();

return 0;
}


The output is :
NO : 0
NO : 1

My question is,how to make test and test2 independent,alt hough they
refer to same function.
That's mean the output is :
NO : 0
NO : 0

[Jakob Bieling]

Re: pointer to function problem

blackrosezy@gma il.com wrote:[color=blue]
> #include <cstdlib>
> #include <iostream>
>
> using namespace std;
>
> int (*test)();
> int (*test2)();
>
> int aku(){
>
> static int i = 0;
> cout << "NO : " << i << endl;
> i++;
> }
>
>
> int main()
> {
>
> test = &aku;
> test2 = &aku;
> (*test)();
> (*test)();
>
> return 0;
> }
>
>
> The output is :
> NO : 0
> NO : 1
>
> My question is,how to make test and test2 independent,alt hough they
> refer to same function.
> That's mean the output is :
> NO : 0
> NO : 0[/color]

You cannot. Unless you create a new function (this includes
different template instanciations) , the static variable inside that
function will have those 'static' semantics you are experiencing.

hth
--
jb

(reply address in rot13, unscramble first)

[Tomás]

Re: pointer to function problem

posted:
[color=blue]
> #include <cstdlib>
> #include <iostream>
>
> using namespace std;
>
> int (*test)();
> int (*test2)();
>
> int aku(){
>
> static int i = 0;
> cout << "NO : " << i << endl;
> i++;
> }
>
>
> int main()
> {
>
> test = &aku;
> test2 = &aku;
> (*test)();
> (*test)();
>
> return 0;
> }
>
>
> The output is :
> NO : 0
> NO : 1
>
> My question is,how to make test and test2 independent,alt hough they
> refer to same function.
> That's mean the output is :
> NO : 0
> NO : 0[/color]

One way comes to mind:


#include <cstdlib>
#include <iostream>

using namespace std;

int (*test)();
extern char const funcpoint_name_ test[] = "test";

int (*test2)();
extern char const funcpoint_name_ test2[] = "test2";


template<const char* name_of_pointer >
int aku()
{

static int i = 0;
cout << "NO : " << i << endl;
++i;
}

int main()
{

test = &aku<funcpoint_ name_test>;

test2 = &aku<funcpoint_ name_test2>;

(*test)();

(*test2)();

return 0;
}

[Jerry Coffin]

Re: pointer to function problem

In article <1142771353.247 507.231190
@v46g2000cwv.go oglegroups.com> , blackrosezy@gma il.com
says...

[ ... ]
[color=blue]
> My question is,how to make test and test2 independent,alt hough they
> refer to same function.
> That's mean the output is :
> NO : 0
> NO : 0[/color]

Using pointers to a function, you can't. You can,
however, create a functor that does the job:

struct aku {
int i;
aku() : i(0) {}

void operator()() {
std::cout << "NO: " << i << std::endl;
++i;
}
};

Each object you create of this type has its own,
independent counter. For example:

int main() {
aku test1;
aku test2;

test1();
test2();
test1();
test2();
return 0;
}

produces:

NO: 0
NO: 0
NO: 1
NO: 1

as its output. I think that's what you wanted anyway.

--
Later,
Jerry.

The universe is a figment of its own imagination.