Overloading a function in C++

[Marko.Cain.23@gmail.com]

Why the following code compiles in C++, it is overloading a funciton
"x" with 2 different return value (one is int, one is void). Is that
legal? Thanks.

class Test1
{
public:
Test1();
virtual ~Test1();

int x() { return _x;}
void x(int x1) { _x = x1;}

private:
int _x;
};

[Sharad Kala]

Re: Overloading a function in C++


<Marko.Cain.23@ gmail.com> wrote in message
| Why the following code compiles in C++, it is overloading a funciton
| "x" with 2 different return value (one is int, one is void). Is that
| legal? Thanks.

You are mistaken. It is not overloading on the return value, in fact you
can't overload on the return value.

| class Test1
| {
| public:
| Test1();
| virtual ~Test1();
|
| int x() { return _x;}

This takes void as parameter and returns int

| void x(int x1) { _x = x1;}

This takes int as parameter and returns void

|
| private:
| int _x;
| };

Sharad

[Jim Langston]

Re: Overloading a function in C++

<Marko.Cain.23@ gmail.com> wrote in message
news:1139898359 .036646.249590@ f14g2000cwb.goo glegroups.com.. .[color=blue]
> Why the following code compiles in C++, it is overloading a funciton
> "x" with 2 different return value (one is int, one is void). Is that
> legal? Thanks.
>
> class Test1
> {
> public:
> Test1();
> virtual ~Test1();
>
> int x() { return _x;}
> void x(int x1) { _x = x1;}
>
> private:
> int _x;
> };[/color]

As long as the parameters are different, and in this case one is void and
one is int, it is legal.

[Marco Wahl]

Re: Overloading a function in C++

Marko.Cain.23@g mail.com writes:
[color=blue]
> class Test1
> {
> public:
> Test1();
> virtual ~Test1();
>
> int x() { return _x;}
> void x(int x1) { _x = x1;}
>
> private:
> int _x;
> };[/color]
[color=blue]
> [...] Is that legal?[/color]

Yes.

Just to make it clear. The following class is illegal in C++.

[[[
/**
This code will not compile.

Cause: Two function-declarations that differ only in the
return-type.
*/
class Test2
{
public:
int x();
void x();
};
]]]

Different return-types can not be used for overloading functions in
C++. Overloading is based on the arguments of functions.

[Tim Slattery]

Re: Overloading a function in C++

Marko.Cain.23@g mail.com wrote:
[color=blue]
>Why the following code compiles in C++, it is overloading a funciton
>"x" with 2 different return value (one is int, one is void). Is that
>legal? Thanks.[/color]
[color=blue]
> int x() { return _x;}
> void x(int x1) { _x = x1;}[/color]

They can't differ *only* by return type. Since these two functions
have different argument lists, your code will work fine.

--
Tim Slattery
Slattery_T@bls. gov