How to use htonl in IPv6

[linuxer]

Hello all,
I have the following program, which will take ipv4 address as input
in command line and convert it from host byte order to network byte
order. I need similar thing to be done for IPv6. Any help is
appriciated. Thanks in advance.

#include <stdio.h>
main( int argc, char *argv[] )
{
unsigned int ip, b1, b2, b3, b4;
ip=b1=b2=b3=b4= 0;

if (sscanf(argv[1], "%d.%d.%d.% d", &b1, &b2, &b3, &b4)
== 4 && b1<=255U && b2<=255U && b3<=255U && b4<=255U) {
//For IPv4 address
ip = htonl( (b1<<24)|(b2<<1 6)|(b3<<8)|b4 );
}
printf("IP_TO_L ONG:%ld\n", ip);
}

[Alf P. Steinbach]

Re: How to use htonl in IPv6

* linuxer:[color=blue]
> Hello all,
> I have the following program, which will take ipv4 address as input
> in command line and convert it from host byte order to network byte
> order. I need similar thing to be done for IPv6. Any help is
> appriciated. Thanks in advance.
>
> #include <stdio.h>
> main( int argc, char *argv[] )
> {
> unsigned int ip, b1, b2, b3, b4;
> ip=b1=b2=b3=b4= 0;
>
> if (sscanf(argv[1], "%d.%d.%d.% d", &b1, &b2, &b3, &b4)
> == 4 && b1<=255U && b2<=255U && b3<=255U && b4<=255U) {
> //For IPv4 address
> ip = htonl( (b1<<24)|(b2<<1 6)|(b3<<8)|b4 );
> }
> printf("IP_TO_L ONG:%ld\n", ip);
> }[/color]

"htonl" is not part of standard C++ or the standard C++ library.

So you're off-topic, and I don't know where to send you, except,
use a search engine such as Google.

The above code should not even compile.

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?

[Maxim Yegorushkin]

Re: How to use htonl in IPv6


linuxer wrote:[color=blue]
> Hello all,
> I have the following program, which will take ipv4 address as input
> in command line and convert it from host byte order to network byte
> order. I need similar thing to be done for IPv6. Any help is
> appriciated. Thanks in advance.[/color]

On Linux use inet_ntop().
man inet_ntop