operator-

[wojtek]

I have a class Foo
class Foo {
...
};
for which I have overloaded the subtraction operator declared as
int operator-(const Foo&, const Foo&);

When I use this:
Foo a, b;
...
int n = a - b;
the compiler looks for the implementation of
int operator-(Foo, const Foo&);
and does not use my operator. If I modify the code to be
Foo a, b;
...
int n = (const Foo&)(a) - (const Foo&)(b);
everything is fine.

I do not understand why I need to cast a and b.

[Victor Bazarov]

Re: operator-

wojtek wrote:[color=blue]
> I have a class Foo
> class Foo {
> ...
> };
> for which I have overloaded the subtraction operator declared as
> int operator-(const Foo&, const Foo&);
>
> When I use this:
> Foo a, b;
> ...
> int n = a - b;
> the compiler looks for the implementation of
> int operator-(Foo, const Foo&);
> and does not use my operator. If I modify the code to be
> Foo a, b;
> ...
> int n = (const Foo&)(a) - (const Foo&)(b);
> everything is fine.
>
> I do not understand why I need to cast a and b.
>[/color]

Do you also have operator int defined in your class, maybe?
In any case, post complete minimal code that reproduces your
problem, read FAQ 5.8.

V