How to implement arctan(x) without using standard library?

Collapse
This topic is closed.
X
X
 
  • Time
  • Show
Clear All
new posts
  • Gerald

    How to implement arctan(x) without using standard library?

    Recently, my program need to be run in embeded enviroment, and I cann't
    use standard library. But I need to use arctan(x), so I implement it
    like the following:

    inline double pow(double x, size_t n) {
    if (n == 0)
    return 1;
    else if (n % 2 == 0)
    return pow(x * x, n >> 1);
    else
    return x * pow(x * x, n >> 1);
    }

    inline double atan_Gerald(dou ble x) {
    register double temp1 = x >= 0 ? x : -x;
    register double temp2 = temp1 <= 1.0 ? temp1 : (temp1 - 1) / (temp1 +
    1);
    register double sum = temp2;

    for (register size_t i = 1; i != 6; ++i)
    sum += (i % 2 ? -1 : 1) * pow(temp2, (i << 1) + 1) / ((i << 1) + 1);

    if (temp1 > 1.0) sum += 0.785398;
    return x >= 0 ? sum : -sum;
    }

    But I found it doesn't work efficiently like atan in standard library,
    Would you please
    help me to optimize my code or give me another suggestion?

    Thank you!

    Regards Gerald

  • Gerald

    #2
    Re: How to implement arctan(x) without using standard library?

    I made a mistake: the 'register' before double is useless, I forget to
    delete it.

    Comment

    • Dietmar Kuehl

      #3
      Re: How to implement arctan(x) without using standard library?

      Gerald wrote:[color=blue]
      > Recently, my program need to be run in embeded enviroment, and I cann't
      > use standard library.[/color]

      I don't think that this is a reasonable argument for not using the
      standard library! In particular, I know that there is at least one
      standard library targeted also at embedded systems: the Dinkumware
      library is available in a version tailored to embedded systems
      (although I personally don't see any justification at all in EC++...).
      See <http://www.dinkumware. com/>. The prices are definitely in a
      range where it comes much cheaper to buy the library than provide a
      quality implementation of even a single trigonometric function.
      [color=blue]
      > But I need to use arctan(x), so I implement it
      > like the following:[/color]

      I haven't implemented these functions myself and thus I might be
      entirely wrong about how I think these functions are implemented.
      Still, my understanding is that they are implemented very different
      from how you tried to implement them. The basic approach is something
      like this:

      1. Translate the function argument(s) to a minimal basic area (this
      is almost certainly not the correct term but I don't know the
      correct term). My maths is rather rusty but I think for arctan(x)
      the basic area is the range [0, 1]: all other values can be
      derived from an appropriate argument:
      - x < 0: arctan(x) = -arctan(-x)
      - 1 < x: arctan(1/x) = pi/2 - arctan(x)
      (actually, you already do this part...)
      2. For the values in basic area you look up the subrange your value
      is located in. Each subrange is associated with an approximation
      function which is just a suitably parameterized polynomial of a
      relatively small degree which can be evaluated reasonably fast.
      The real tricky thing is to determine suitable subranges and the
      parameters for their approximating polynomials. I have no idea
      at all how this done.
      --
      <mailto:dietmar _kuehl@yahoo.co m> <http://www.dietmar-kuehl.de/>
      <http://www.eai-systems.com> - Efficient Artificial Intelligence

      Comment

      • Earl Purple

        #4
        Re: How to implement arctan(x) without using standard library?


        Dietmar Kuehl wrote:[color=blue]
        > I haven't implemented these functions myself and thus I might be
        > entirely wrong about how I think these functions are implemented.
        > Still, my understanding is that they are implemented very different
        > from how you tried to implement them. The basic approach is something
        > like this:
        >
        > 1. Translate the function argument(s) to a minimal basic area (this
        > is almost certainly not the correct term but I don't know the
        > correct term). My maths is rather rusty but I think for arctan(x)
        > the basic area is the range [0, 1]: all other values can be
        > derived from an appropriate argument:
        > - x < 0: arctan(x) = -arctan(-x)
        > - 1 < x: arctan(1/x) = pi/2 - arctan(x)
        > (actually, you already do this part...)
        > 2. For the values in basic area you look up the subrange your value
        > is located in. Each subrange is associated with an approximation
        > function which is just a suitably parameterized polynomial of a
        > relatively small degree which can be evaluated reasonably fast.
        > The real tricky thing is to determine suitable subranges and the
        > parameters for their approximating polynomials. I have no idea
        > at all how this done.
        > --
        > <mailto:dietmar _kuehl@yahoo.co m> <http://www.dietmar-kuehl.de/>
        > <http://www.eai-systems.com> - Efficient Artificial Intelligence[/color]

        For good accuracy use cubic splines. For optimal speed use a bigger
        caching table and linear progression between the points. (A cubic
        spline has 4 parameters in each range so using the linear version you
        can store in theory 5 times as many points).

        Comment

        • Earl Purple

          #5
          Re: How to implement arctan(x) without using standard library?

          Of course you don't have to store the cubic spline parameters as they
          can be worked out
          from the cached value, but that would give you even slower performance.

          Comment

          • Michiel.Salters@tomtom.com

            #6
            Re: How to implement arctan(x) without using standard library?

            Dietmar Kuehl wrote:[color=blue]
            > Gerald wrote:[color=green]
            > > Recently, my program need to be run in embeded enviroment, and I cann't
            > > use standard library.
            > > But I need to use arctan(x)[/color]
            > The basic approach is something like this:
            >
            > 1. Translate the function argument(s) to a minimal basic area (this
            > is almost certainly not the correct term but I don't know the
            > correct term). My maths is rather rusty but I think for arctan(x)
            > the basic area is the range [0, 1]: all other values can be
            > derived from an appropriate argument:
            > - x < 0: arctan(x) = -arctan(-x)
            > - 1 < x: arctan(1/x) = pi/2 - arctan(x)
            > (actually, you already do this part...)[/color]

            There are two kinds of reductions. The first one is to keep the tables
            finite
            (This is essential for e.g. sin(x), as x may be any value) and the
            second is
            just to reduce the table size. The latter is something to worry about
            later.
            (It's a classic time/space tradeoff you'd need to profile).
            [color=blue]
            > 2. For the values in basic area you look up the subrange your value
            > is located in. Each subrange is associated with an approximation
            > function which is just a suitably parameterized polynomial of a
            > relatively small degree which can be evaluated reasonably fast.
            > The real tricky thing is to determine suitable subranges and the
            > parameters for their approximating polynomials. I have no idea
            > at all how this done.[/color]

            Polynomials are very efficient in finding the first few digits, but may
            be terrible
            in finding the next. E.g. when you already have arctan(x)=0.23. ...
            you'd need
            to look in table 23 to get the next coefficients, which implies 100
            tables.
            That's nog good for embedded systems. (Of course, real systems probably
            use nibbles not digits, so you'd need 256 tables after the first two
            nibbles)

            However, it seems a real arctan algorithm is a lot more complex:


            I wouldn't invent that myselves. Implementing the basic CORDIC seems
            easy, though.

            HTH,
            Michiel Salters

            Comment

            Working...