Why am I getting floating point exception?

[Steven Jones]

Im just learning C an do not understand why the following code fails.
The while loop apperas to work fine until it bombs out with a
floating point exception. Whats going on?

Thanks


/*
* chapter 5, program 7
* Calculate GCD of two numbers.
*/

#include <stdio.h>

main ()
{
int u,v, temp;

temp = -1; // *** DEBUG
printf("Please type two non-negative integers.\n");

scanf("%d%d", &u,&v);

printf("\n\nThe GCD of %d and %d is ", u,v);

while ( u != 0)
{
printf ("\nu v temp ---> %d\t%d\t%d",u, v, temp); // *** DEBUG
temp = u % v;
u = v;
v = temp;
}

// printf("%d\n", u);

}


**** OUTPUT:

[sj@KUTI pic]$ a.out
Please type two non-negative integers.
150 35


The GCD of 150 and 35 is
u v temp ---> 150 35 -1
u v temp ---> 35 10 10
u v temp ---> 10 5 5
Floating point exception

[pete]

Re: Why am I getting floating point exception?

Steven Jones wrote:
[color=blue]
> while ( u != 0)[/color]

while (v != 0)
[color=blue]
> {
> printf ("\nu v temp ---> %d\t%d\t%d",u, v, temp); // *** DEBUG
> temp = u % v;
> u = v;
> v = temp;
> }[/color]

--
pete

[Jordan Abel]

Re: Why am I getting floating point exception?

On 2005-10-30, Steven Jones <caja@swbell.ne t> wrote:[color=blue]
> Im just learning C an do not understand why the following code fails.
> The while loop apperas to work fine until it bombs out with a
> floating point exception. Whats going on?[/color]

Probable reasons for a floating point exception involving integers include:
Trap representations of signed types [unlikely on modern systems]
Overflow on signed types
Division by zero.
[color=blue]
> while ( u != 0)
> {
> printf ("\nu v temp ---> %d\t%d\t%d",u, v, temp); // *** DEBUG
> temp = u % v;[/color]
If 'v' reaches zero, you will have a division by zero here.[color=blue]
> u = v;
> v = temp;
> }[/color]