Multi-dimensional array initialization

[masood.iqbal@lycos.com]

Hi,

I have seen at least two ways to initialize multi-dimensional arrays in
C. One of the ways is shown in a sample code snippet below. The other
way does not make use of any intermediate braces. In other words, all
the entries are listed under the same pair of enclosing braces. For
example:

char* mdTbl[3][5] = { "One", "Two", "Three", "Four","Fiv e", "Six",
"Seven",
"Eight", "Nine", "Ten", "Eleven", "Twelve",
"Thirteen",
"Fourteen", "Fifteen" };

Are the two approaches exactly identical, or is there any difference
between them?

Thanks,
Masood
/*************** *************** *************** *********
*************** *************** *************** *********/

#include <stdio.h>


char* mdTbl[3][5] = {
{
"One",
"Two",
"Three",
"Four",
"Five"
},
{
"Six",
"Seven",
"Eight",
"Nine",
"Ten"
},
{
"Eleven",
"Twelve",
"Thirteen",
"Fourteen",
"Fifteen"
},
};


void
print_array_ele ment(int row, int column)
{
printf("%s\n", mdTbl[row][column]);
}

main()
{
print_array_ele ment(2, 2);
}

[pete]

Re: Multi-dimensional array initialization

masood.iqbal@ly cos.com wrote:[color=blue]
>
> Hi,
>
> I have seen at least two ways to
> initialize multi-dimensional arrays in C.
> One of the ways is shown in a sample code snippet below. The other
> way does not make use of any intermediate braces. In other words, all
> the entries are listed under the same pair of enclosing braces. For
> example:
>
> char* mdTbl[3][5] = { "One", "Two", "Three", "Four","Fiv e", "Six",
> "Seven",
> "Eight", "Nine", "Ten", "Eleven", "Twelve",
> "Thirteen",
> "Fourteen", "Fifteen" };
>
> Are the two approaches exactly identical,[/color]

Yes.
The left most brackets may be left empty in an array initialization.

char* mdTbl[][5] = {
"One", "Two", "Three", "Four","Fiv e", "Six",
"Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve",
"Thirteen","Fou rteen", "Fifteen"
};

--
pete