question, about implicit conversions

[Mason Verger]

Given:



int center = 0;

int range = 5;

int lower = 0;

What does this statement do? Is range converted to a float then divided by 2
then casted back to int?

center = ((range)/2) + lower;

[Martin Ambuhl]

Re: question, about implicit conversions

Mason Verger wrote:
[color=blue]
> Given:
> int center = 0;
> int range = 5;
> int lower = 0;
>
> What does this statement do? Is range converted to a float then divided by 2
> then casted back to int?[/color]

No. range is an int, 2 is an int, so range/2 does integer division.
[color=blue]
> center = ((range)/2) + lower;[/color]
range = 5
range/2 = 5/2 = 2
lower = 0
(range/2) + lower = 2 + 0 = 2
center = 2

But with either of the following (or many other similar forms)
(range/2.) + lower
((double)range/2) + lower
the RHS is 2.5, and the assignment to an int now drops the fractional part.
center becomes 2 in this case as well.





--
Martin Ambuhl

[Mike Wahler]

Re: question, about implicit conversions


Mason Verger <mason_verger@s kincare.com> wrote in message
news:iCS9b.515$ t93.345@nwrddc0 2.gnilink.net.. .[color=blue]
> Given:
>
>
>
> int center = 0;
>
> int range = 5;
>
> int lower = 0;
>
> What does this statement do?
>
> center = ((range)/2) + lower;[/color]
[color=blue]
> Is range converted to a float[/color]

No.
[color=blue]
>then divided by 2[/color]

It's divided by two using 'integer division', which
will truncate any remainder. I.e. range / 2 will
give a result of 2.
[color=blue]
> then casted back to int?[/color]

No conversions or casts are performed in your example.
All your operands already have the same type.


-Mike