[Fwd: <string>.replace]

[Billy N. Patton]

-------- Original Message --------
Subject: <string>.replac e
Date: Fri, 15 Oct 2004 11:07:19 -0500
From: Billy N. Patton <b-patton@ti.com>
Organization: Texas Instruments
Newsgroups: alt.comp.lang.l earn.c-c++

I'm trying to remove the \n from a string.
If I just simply locate teh char and replace it with \0 then the
destructor should only delete up to the \0 and leave 1 char unrecovered.

Here is what I've tried several times

From my documentation
basic_string &replace( size_type index, size_type num, const
basic_string &str );

bool ExCommand(strin g& cmd,vector<stri ng>& ret)
{
string s;
static char buf[BUFSZ];
FILE *ptr = NULL;

if (cmd.empty()) return false;

if ((ptr = popen(cmd.c_str (), "r")) NE NULL)
{
while (fgets(buf, BUFSZ, ptr) NE NULL)
{
s = buf;
s.replace(s.len gth()-1,1,"\n");
cout << "'" << s << "'\n";
ret.push_back(s );
}
pclose(ptr);
}
else
{
return false;
}
return true;
}


The cout prints :
'./TEST.cxx
'

It's not replacing the \n

I've tried s.length() without the -1 with the same results.

--
___ _ ____ ___ __ __
/ _ )(_) / /_ __ / _ \___ _/ /_/ /____ ___
/ _ / / / / // / / ___/ _ `/ __/ __/ _ \/ _ \
/____/_/_/_/\_, / /_/ \_,_/\__/\__/\___/_//_/
/___/
Texas Instruments ASIC Circuit Design Methodlogy Group
Dallas, Texas, 214-480-4455, b-patton@ti.com

--
___ _ ____ ___ __ __
/ _ )(_) / /_ __ / _ \___ _/ /_/ /____ ___
/ _ / / / / // / / ___/ _ `/ __/ __/ _ \/ _ \
/____/_/_/_/\_, / /_/ \_,_/\__/\__/\___/_//_/
/___/
Texas Instruments ASIC Circuit Design Methodlogy Group
Dallas, Texas, 214-480-4455, b-patton@ti.com

[Howard]

Re: &lt;string&gt;. replace]


"Billy N. Patton" <b-patton@ti.com> wrote in message
news:ckpcoj$jl7 $2@home.itg.ti. com...[color=blue]
>
>
> -------- Original Message --------
> Subject: <string>.replac e
> Date: Fri, 15 Oct 2004 11:07:19 -0500
> From: Billy N. Patton <b-patton@ti.com>
> Organization: Texas Instruments
> Newsgroups: alt.comp.lang.l earn.c-c++
>
> I'm trying to remove the \n from a string.
> If I just simply locate teh char and replace it with \0 then the
> destructor should only delete up to the \0 and leave 1 char unrecovered.
>
> Here is what I've tried several times
>
> From my documentation
> basic_string &replace( size_type index, size_type num, const
> basic_string &str );
>
> bool ExCommand(strin g& cmd,vector<stri ng>& ret)
> {
> string s;
> static char buf[BUFSZ];
> FILE *ptr = NULL;
>
> if (cmd.empty()) return false;
>
> if ((ptr = popen(cmd.c_str (), "r")) NE NULL)
> {
> while (fgets(buf, BUFSZ, ptr) NE NULL)
> {
> s = buf;
> s.replace(s.len gth()-1,1,"\n");[/color]

According to my books, that call replaces the last character of the string
with '\n'. The first parameter is where to start: length-1 is the last
characeter. The second parameter is how many to replace: 1, just that last
character. The last parameter is the string to replace it *with*: '\n'. So
you change the last character of the string to a '\n' character. I'm
guessing that the last character of the string already *was* the '\n'
character...?
[color=blue]
> cout << "'" << s << "'\n";[/color]

Here, after writing out a single quote, and the string with its (new) CR/LF,
you then output a single quote and another CR/LF. So what you see below is
exactly what you asked for.


Unfortunately, I only know what it's doing. I don't know how to do what you
want without further study. :-(

-Howard

[color=blue]
> ret.push_back(s );
> }
> pclose(ptr);
> }
> else
> {
> return false;
> }
> return true;
> }
>
>
> The cout prints :
> './TEST.cxx
> '
>
> It's not replacing the \n
>
> I've tried s.length() without the -1 with the same results.
>
> --
> ___ _ ____ ___ __ __
> / _ )(_) / /_ __ / _ \___ _/ /_/ /____ ___
> / _ / / / / // / / ___/ _ `/ __/ __/ _ \/ _ \
> /____/_/_/_/\_, / /_/ \_,_/\__/\__/\___/_//_/
> /___/
> Texas Instruments ASIC Circuit Design Methodlogy Group
> Dallas, Texas, 214-480-4455, b-patton@ti.com
>
> --
> ___ _ ____ ___ __ __
> / _ )(_) / /_ __ / _ \___ _/ /_/ /____ ___
> / _ / / / / // / / ___/ _ `/ __/ __/ _ \/ _ \
> /____/_/_/_/\_, / /_/ \_,_/\__/\__/\___/_//_/
> /___/
> Texas Instruments ASIC Circuit Design Methodlogy Group
> Dallas, Texas, 214-480-4455, b-patton@ti.com[/color]