template export question

[New_user]

Hello.

Excerpt from ISO/IEC 14882 :
14/6
A namespace-scope declaration or definition of ........skipped ...... a non-
inline member function of a class template or a static data member of a class
template may be preceded by the export keyword.

and from http://www.comeaucomputing.com/4.3.0...5+/43stuff.txt :
A template must be declared export at both the point of definition and
the point of reference.

I have some files:

//templ.h
template<class T>
class A
{
public:
void fun();
static int i_;
};
//I want to export A<T>::fun and A<T>::i_, but I do not want to declare class
//A as exported

//def.cpp
//1!
//exported definitions are here, ordering problems?
//fun first declared as non-exported and later as exported?

export template<class T>
void A<T>::fun()
{
}

export template<class T>
int A<T>::i_ = 0;

//user.cpp
//2! here's class usage

#include "templ.h"

int main()
{
A<int>a;
a.fun();
}

How can I declare A<T>::fun in user.cpp as exported at the point of reference?

[Sumit Rajan]

Re: template export question


"New_user" <tpochep@mail.r u> wrote in message
news:d29bee5d.0 404070312.e8ad6 39@posting.goog le.com...[color=blue]
> Hello.
>
> Excerpt from ISO/IEC 14882 :
> 14/6
> A namespace-scope declaration or definition of ........skipped ...... a[/color]
non-[color=blue]
> inline member function of a class template or a static data member of a[/color]
class[color=blue]
> template may be preceded by the export keyword.
>
> and from http://www.comeaucomputing.com/4.3.0...5+/43stuff.txt :
> A template must be declared export at both the point of definition and
> the point of reference.
>
> I have some files:
>
> //templ.h
> template<class T>
> class A
> {
> public:
> void fun();
> static int i_;
> };
> //I want to export A<T>::fun and A<T>::i_, but I do not want to declare[/color]
class[color=blue]
> //A as exported[/color]

The effect would be exactly the same if you do this:

//templ.h
export template <class T>
class A {
public:
void fun();
static int i_;
};


"export" in def.cpp is then redundant.

//def.cpp

#include "templ.h"

template<class T>
void A<T>::fun()
{}

template<class T>
int A<T>::i_ = 0;



Regards,
Sumit.

[color=blue]
> //def.cpp
> //1!
> //exported definitions are here, ordering problems?
> //fun first declared as non-exported and later as exported?
>
> export template<class T>
> void A<T>::fun()
> {
> }
>
> export template<class T>
> int A<T>::i_ = 0;
>
> //user.cpp
> //2! here's class usage
>
> #include "templ.h"
>
> int main()
> {
> A<int>a;
> a.fun();
> }
>
> How can I declare A<T>::fun in user.cpp as exported at the point of[/color]
reference?

[Sumit Rajan]

Re: template export question


"New_user" <tpochep@mail.r u> wrote in message
news:d29bee5d.0 404070312.e8ad6 39@posting.goog le.com...[color=blue]
> Hello.
>
> Excerpt from ISO/IEC 14882 :
> 14/6
> A namespace-scope declaration or definition of ........skipped ...... a[/color]
non-[color=blue]
> inline member function of a class template or a static data member of a[/color]
class[color=blue]
> template may be preceded by the export keyword.
>
> and from http://www.comeaucomputing.com/4.3.0...5+/43stuff.txt :
> A template must be declared export at both the point of definition and
> the point of reference.
>
> I have some files:
>
> //templ.h
> template<class T>
> class A
> {
> public:
> void fun();
> static int i_;
> };
> //I want to export A<T>::fun and A<T>::i_, but I do not want to declare[/color]
class[color=blue]
> //A as exported[/color]

The effect would be exactly the same if you do this:

//templ.h
export template <class T>
class A {
public:
void fun();
static int i_;
};


"export" in def.cpp is then redundant.

//def.cpp

#include "templ.h"

template<class T>
void A<T>::fun()
{}

template<class T>
int A<T>::i_ = 0;



Regards,
Sumit.

[color=blue]
> //def.cpp
> //1!
> //exported definitions are here, ordering problems?
> //fun first declared as non-exported and later as exported?
>
> export template<class T>
> void A<T>::fun()
> {
> }
>
> export template<class T>
> int A<T>::i_ = 0;
>
> //user.cpp
> //2! here's class usage
>
> #include "templ.h"
>
> int main()
> {
> A<int>a;
> a.fun();
> }
>
> How can I declare A<T>::fun in user.cpp as exported at the point of[/color]
reference?

[Sumit Rajan]

Re: template export question


"Sumit Rajan" <sumitrajan@myr ealbox.com> wrote in message
news:c511ro$2mc 9ee$1@ID-206022.news.uni-berlin.de...[color=blue]
>
> "New_user" <tpochep@mail.r u> wrote in message
> news:d29bee5d.0 404070312.e8ad6 39@posting.goog le.com...[/color]
[color=blue][color=green][color=darkred]
> > > How can I declare A<T>::fun in user.cpp as exported at the point of[/color][/color]
> reference?
>[/color]


Sorry. Please disregard that post. I missed that question when I read
through your message. :-)

[Sumit Rajan]

Re: template export question


"Sumit Rajan" <sumitrajan@myr ealbox.com> wrote in message
news:c511ro$2mc 9ee$1@ID-206022.news.uni-berlin.de...[color=blue]
>
> "New_user" <tpochep@mail.r u> wrote in message
> news:d29bee5d.0 404070312.e8ad6 39@posting.goog le.com...[/color]
[color=blue][color=green][color=darkred]
> > > How can I declare A<T>::fun in user.cpp as exported at the point of[/color][/color]
> reference?
>[/color]


Sorry. Please disregard that post. I missed that question when I read
through your message. :-)

[Sumit Rajan]

Re: template export question


"Sumit Rajan" <sumitrajan@myr ealbox.com> wrote in message
news:c511ro$2mc 9ee$1@ID-206022.news.uni-berlin.de...[color=blue]
>
> "New_user" <tpochep@mail.r u> wrote in message
> news:d29bee5d.0 404070312.e8ad6 39@posting.goog le.com...[/color]
[color=blue][color=green][color=darkred]
> > > How can I declare A<T>::fun in user.cpp as exported at the point of[/color][/color]
> reference?
>[/color]


Sorry. Please disregard that post. I missed that question when I read
through your message. :-)

[Sumit Rajan]

Re: template export question


"Sumit Rajan" <sumitrajan@myr ealbox.com> wrote in message
news:c511ro$2mc 9ee$1@ID-206022.news.uni-berlin.de...[color=blue]
>
> "New_user" <tpochep@mail.r u> wrote in message
> news:d29bee5d.0 404070312.e8ad6 39@posting.goog le.com...[/color]
[color=blue][color=green][color=darkred]
> > > How can I declare A<T>::fun in user.cpp as exported at the point of[/color][/color]
> reference?
>[/color]


Sorry. Please disregard that post. I missed that question when I read
through your message. :-)

[Denis Remezov]

Re: template export question

New_user wrote:[color=blue]
>
> Hello.
>
> Excerpt from ISO/IEC 14882 :
> 14/6
> A namespace-scope declaration or definition of ........skipped ...... a non-
> inline member function of a class template or a static data member of a class
> template may be preceded by the export keyword.
>
> and from http://www.comeaucomputing.com/4.3.0...5+/43stuff.txt :
> A template must be declared export at both the point of definition and
> the point of reference.
>[/color]
[snip][color=blue]
>
> How can I declare A<T>::fun in user.cpp as exported at the point of reference?[/color]

If I understand you correctly you don't want to declare your templates with the
export keyword at the point you are using them and still want them to be resolved
as exported? If so, I would guess that would not do. I take 14/6 and 14/8 to mean
that the first declaration of exported templates in /each/ of the translation units
must use the export keyword; subsequent redeclarations or definitions do not need to
use "export"; one and only one of the translation units must provide a definition.

I am not quite sure and would like to confirm if the above is correct, for myself.

It may sound ugly, but if you don't want to go the inclusion way I'd consider
explicit instantiation.

Denis

[Denis Remezov]

Re: template export question

New_user wrote:[color=blue]
>
> Hello.
>
> Excerpt from ISO/IEC 14882 :
> 14/6
> A namespace-scope declaration or definition of ........skipped ...... a non-
> inline member function of a class template or a static data member of a class
> template may be preceded by the export keyword.
>
> and from http://www.comeaucomputing.com/4.3.0...5+/43stuff.txt :
> A template must be declared export at both the point of definition and
> the point of reference.
>[/color]
[snip][color=blue]
>
> How can I declare A<T>::fun in user.cpp as exported at the point of reference?[/color]

If I understand you correctly you don't want to declare your templates with the
export keyword at the point you are using them and still want them to be resolved
as exported? If so, I would guess that would not do. I take 14/6 and 14/8 to mean
that the first declaration of exported templates in /each/ of the translation units
must use the export keyword; subsequent redeclarations or definitions do not need to
use "export"; one and only one of the translation units must provide a definition.

I am not quite sure and would like to confirm if the above is correct, for myself.

It may sound ugly, but if you don't want to go the inclusion way I'd consider
explicit instantiation.

Denis

[New_user]

Re: template export question

Hello, Denis.
[color=blue]
> If I understand you correctly you don't want to declare your templates with the
> export keyword at the point you are using them and still want them to be resolved
> as exported?[/color]

No. I just want to understand, how can I declare a non-inline
member-function of a class template (not a member template) or how can
I declare a static data-member of a class template as exported? It
seems to me, the only way is to declare class as exported. But
Standard says, that declaration of a non-inline member-function (or
static data-member) can be preceeded by the 'export' keyword.

[New_user]

Re: template export question

Hello, Denis.
[color=blue]
> If I understand you correctly you don't want to declare your templates with the
> export keyword at the point you are using them and still want them to be resolved
> as exported?[/color]

No. I just want to understand, how can I declare a non-inline
member-function of a class template (not a member template) or how can
I declare a static data-member of a class template as exported? It
seems to me, the only way is to declare class as exported. But
Standard says, that declaration of a non-inline member-function (or
static data-member) can be preceeded by the 'export' keyword.