C++ static character array...

[John Ratliff]

How can you define a static character pointer array in C++?

ex:

class tmp {
private:
static const char *ARR[];
};

const char *tmp::ARR[] =
{
"nts1", "nts2", "nts3"
}

--- This doesn't compile for me, even if I switch it to use two *'s and
abandon the [].

---

However, this is valid:

static const char *ARR[] =
{
"nts1", "nts2", "nts3"
}

This will work, but I would like to know how to embed the declaration
inside a class.

Thanks,

--Dominic

[Rob Williscroft]

Re: C++ static character array...

John Ratliff wrote in news:bv6gis$ijm $1@hood.uits.in diana.edu:
[color=blue]
> How can you define a static character pointer array in C++?
>
> ex:
>
> class tmp {
> private:
> static const char *ARR[];
> };
>
> const char *tmp::ARR[] =
> {
> "nts1", "nts2", "nts3"
> }[/color]

;
[color=blue]
>[/color]

With the missing ; added this compiles fine, what is your error message.
[color=blue]
> --- This doesn't compile for me, even if I switch it to use two *'s and
> abandon the [].
>[/color]

Rob.
--

http://www.victim-prime.dsl.pipex.com/

[John Ratliff]

Re: C++ static character array...

-- temp.cc --
#include <iostream>

using namespace std;

class tc {
private:
static const char **ARR;
public:
void print();
};

const char **tc::ARR =
{
"hello", "world", "there"
};

void tc::print() {
for (int i = 0; i < 3; i++) {
cout << ARR[i] << endl;
}
}

int main(int argc, char **argv) {
tc app;

app.print();

return 0;
}
--- end of temp.cc

g++ temp.cc
test.cc:15: initializer for scalar variable requires one element

What is the difference between

const char **var and const char *var[]?

--Dominic

"Rob Williscroft" <rtw@freenet.RE MOVE.co.uk> wrote in message
news:Xns947DCFD D950D5ukcoREMOV Efreenetrtw@195 .129.110.131...[color=blue]
> John Ratliff wrote in news:bv6gis$ijm $1@hood.uits.in diana.edu:
>[color=green]
> > How can you define a static character pointer array in C++?
> >
> > ex:
> >
> > class tmp {
> > private:
> > static const char *ARR[];
> > };
> >
> > const char *tmp::ARR[] =
> > {
> > "nts1", "nts2", "nts3"
> > }[/color]
>
> ;
>[color=green]
> >[/color]
>
> With the missing ; added this compiles fine, what is your error message.
>[color=green]
> > --- This doesn't compile for me, even if I switch it to use two *'s and
> > abandon the [].
> >[/color]
>
> Rob.
> --
> http://www.victim-prime.dsl.pipex.com/[/color]

[Ron Natalie]

Re: C++ static character array...


"John Ratliff" <jdr@nospam.com > wrote in message news:101idi38gm cvoa4@corp.supe rnews.com...
[color=blue]
>
> What is the difference between
>
> const char **var and const char *var[]?
>[/color]
The first is a pointer to a pointer to const char.
The second is an array (length unspecified) of pointers to const char.

Despite much confusion on newbie programmers part and the fact that
there is an implicit array to pointer conversion, ARRAYS and POINTERS
ARE NOT THE SAME THING.

const char**x = { "a", "b" };

fails because you are trying to use an aggregate initalizer to initialize something
that's not an aggregate. x points to exactly one thing, which is another pointer.

const char * x[] = { "a", "b" };

works because x is now an array of multiple things, so you can use the aggregate
initializer to set each of them. The things inside the {} are now valid initializers
for each const char* that is in the array.

[John Ratliff]

Re: C++ static character array...


"Ron Natalie" <ron@sensor.com > wrote in message
news:40193a14$0 $234$9a6e19ea@n ews.newshosting .com...[color=blue]
>
> "John Ratliff" <jdr@nospam.com > wrote in message[/color]
news:101idi38gm cvoa4@corp.supe rnews.com...[color=blue]
>[color=green]
> >
> > What is the difference between
> >
> > const char **var and const char *var[]?
> >[/color]
> The first is a pointer to a pointer to const char.
> The second is an array (length unspecified) of pointers to const char.
>
> Despite much confusion on newbie programmers part and the fact that
> there is an implicit array to pointer conversion, ARRAYS and POINTERS
> ARE NOT THE SAME THING.
>
> const char**x = { "a", "b" };
>
> fails because you are trying to use an aggregate initalizer to initialize[/color]
something[color=blue]
> that's not an aggregate. x points to exactly one thing, which is[/color]
another pointer.[color=blue]
>
> const char * x[] = { "a", "b" };
>
> works because x is now an array of multiple things, so you can use the[/color]
aggregate[color=blue]
> initializer to set each of them. The things inside the {} are now valid[/color]
initializers[color=blue]
> for each const char* that is in the array.[/color]

Thanks.

P.S. Sorry for top-posting. I didn't know...

---
"I'm learnding." (--Ralph Wiggum)