access to member of a class by name;

[danmath06@gmail.com]

If I have an Object and a string wich is the name of a member of the
object, how can I access the member. I'm trying to do something
similar to the DisplayMember property the ListBox has. I'm adding some
functionality to the ListView control, and I would like it to have a
method that takes a collection of objects and an array of member names
to know which members to display.

[Peter Duniho]

Re: access to member of a class by name;

On Sat, 08 Nov 2008 17:34:09 -0800, <danmath06@gmai l.comwrote:

If I have an Object and a string wich is the name of a member of the
object, how can I access the member. I'm trying to do something
similar to the DisplayMember property the ListBox has. I'm adding some
functionality to the ListView control, and I would like it to have a
method that takes a collection of objects and an array of member names
to know which members to display.

You'll need reflection for that. You can call GetType() on the object,
then call Type.GetMember( ) on that Type instance to retrieve information
about the actual member, from which you can then do whatever you need to
get a value for your purposes.

You might want to consider limiting the feature to properties. That would
simplify the code doing the reflection, as well as encourage clients of
your class to encapsulate things better. :) In that case, you can just
call Type.GetPropert y() instead.

Pete

[danmath06@gmail.com]

Re: access to member of a class by name;

Changed my mind:
I want to add 2 methods
1- addcolumn (column_name, width, display member)
2- additems (collection)

[danmath06@gmail.com]

Re: access to member of a class by name;

On Nov 8, 10:46 pm, "Peter Duniho" <NpOeStPe...@nn owslpianmk.com>
wrote:

On Sat, 08 Nov 2008 17:34:09 -0800, <danmat...@gmai l.comwrote:

If I have an Object and a string wich is the name of a member of the
object, how can I access the member. I'm trying to do something
similar to the DisplayMember property the ListBox has. I'm adding some
functionality to the ListView control, and I would like it to have a
method that takes a collection of objects and an array of member names
to know which members to display.

>
You'll need reflection for that. You can call GetType() on the object,
then call Type.GetMember( ) on that Type instance to retrieve information
about the actual member, from which you can then do whatever you need to
get a value for your purposes.
>
You might want to consider limiting the feature to properties. That would
simplify the code doing the reflection, as well as encourage clients of
your class to encapsulate things better. :) In that case, you can just
call Type.GetPropert y() instead.
>
Pete

thanks pete.

I tried this as a test and it worked:

private void getmember (object o, string member){

Type type = o.GetType();

System.Reflecti on.PropertyInfo info =
type.GetPropert y("Nombre");


MessageBox.Show (info.GetValue( o,null).ToStrin g());

}

[danmath06@gmail.com]

Re: access to member of a class by name;

On Nov 8, 11:07 pm, danmat...@gmail .com wrote:

On Nov 8, 10:46 pm, "Peter Duniho" <NpOeStPe...@nn owslpianmk.com>
wrote:
>
>
>

On Sat, 08 Nov 2008 17:34:09 -0800, <danmat...@gmai l.comwrote:

If I have an Object and a string wich is the name of a member of the
object, how can I access the member. I'm trying to do something
similar to the DisplayMember property the ListBox has. I'm adding some
functionality to the ListView control, and I would like it to have a
method that takes a collection of objects and an array of member names
to know which members to display.

>

You'll need reflection for that. You can call GetType() on the object,
then call Type.GetMember( ) on that Type instance to retrieve information
about the actual member, from which you can then do whatever you need to
get a value for your purposes.

>

You might want to consider limiting the feature to properties. That would
simplify the code doing the reflection, as well as encourage clients of
your class to encapsulate things better. :) In that case, you can just
call Type.GetPropert y() instead.

>

Pete

>
thanks pete.
>
I tried this as a test and it worked:
>
private void getmember (object o, string member){
>
Type type = o.GetType();
>
System.Reflecti on.PropertyInfo info =
type.GetPropert y("Nombre");
>
MessageBox.Show (info.GetValue( o,null).ToStrin g());
>
}

I meant 'member' not 'nombre':

private void getmember (object o, string member){

Type type = o.GetType();

System.Reflecti on.PropertyInfo info =
type.GetPropert y(member);


MessageBox.Show (info.GetValue( o,null).ToStrin g());

}