Reverse XmlNodeList Order

[eggie5@gmail.com]

Hi,

I have an XmlNodeList and I need to reverse it. Just like
Array.Reverse() , but it has to stay as an XmlNodeList.

Any ideas?

[Sergey Poberezovskiy]

RE: Reverse XmlNodeList Order

You could try something like

List<XmlNodechi ldren = new List<XmlNode>() ;
foreach (XmlNode child in myNode.ChildNod es)
{
children.Add(my Node.Remove(chi ld));
}
for (int i = children.Count - 1; i >= 0; i--)
{
myNode.AppendCh ild(children[i]);
}

It may not be the fastest, but it is a way. I have not tested it, but it
should be pretty close to the real thing :-)

HTH

"eggie5@gmail.c om" wrote:

Hi,
>
I have an XmlNodeList and I need to reverse it. Just like
Array.Reverse() , but it has to stay as an XmlNodeList.
>
Any ideas?
>
>

[Marc Gravell]

Re: Reverse XmlNodeList Order

OK... this is downright dirty, but it seems to work...

It does at least mean that it stays in sync with the source document (if
that respects updates... not sure)...

Marc

public class ReverseXmlList : XmlNodeList {
private readonly XmlNodeList _source;
public ReverseXmlList( XmlNodeList source)
{
_source = source;
}
public override XmlNode Item(int index)
{
return _source.Item(Co unt - (index + 1));
}
public override System.Collecti ons.IEnumerator GetEnumerator()
{
for (int i = Count - 1; i >= 0; i--)
{
yield return _source.Item(i) ;
}
}
public override int Count
{
get { return _source.Count; }
}
}
static void Main(string[] args)
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(@"< Xml><A/><B/><C/></Xml>");
XmlNodeList original = doc.DocumentEle ment.ChildNodes ;
XmlNodeList reverse = new ReverseXmlList( original);
foreach (XmlNode node in reverse)
{
Debug.WriteLine (node.Name);
}
Debug.WriteLine (reverse[0].Name);
Debug.WriteLine (reverse.Item(0 ).Name);
}

[eggie5]

Re: Reverse XmlNodeList Order

Hi,

What is myNode in your example? I need a reversed XmlNodeList to be
returned.

On Oct 31, 4:00 am, Sergey Poberezovskiy
<SergeyPoberezo vs...@discussio ns.microsoft.co mwrote:

You could try something like
>
List<XmlNodechi ldren = new List<XmlNode>() ;
foreach (XmlNode child in myNode.ChildNod es)
{
children.Add(my Node.Remove(chi ld));}for (int i = children.Count - 1; i >= 0; i--)
{
myNode.AppendCh ild(children[i]);
>
}It may not be the fastest, but it is a way. I have not tested it, but it
should be pretty close to the real thing :-)
>
HTH
>
"egg...@gmail.c om" wrote:

Hi,

>

I have an XmlNodeList and I need to reverse it. Just like
Array.Reverse() , but it has to stay as an XmlNodeList.

>

Any ideas?

[eggie5]

Re: Reverse XmlNodeList Order

Thanks your class works great!

On Oct 31, 4:19 am, "Marc Gravell" <marc.grav...@g mail.comwrote:

OK... this is downright dirty, but it seems to work...
>
It does at least mean that it stays in sync with the source document (if
that respects updates... not sure)...
>
Marc
>
public class ReverseXmlList : XmlNodeList {
private readonly XmlNodeList _source;
public ReverseXmlList( XmlNodeList source)
{
_source = source;
}
public override XmlNode Item(int index)
{
return _source.Item(Co unt - (index + 1));
}
public override System.Collecti ons.IEnumerator GetEnumerator()
{
for (int i = Count - 1; i >= 0; i--)
{
yield return _source.Item(i) ;
}
}
public override int Count
{
get { return _source.Count; }
}
}
static void Main(string[] args)
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(@"< Xml><A/><B/><C/></Xml>");
XmlNodeList original = doc.DocumentEle ment.ChildNodes ;
XmlNodeList reverse = new ReverseXmlList( original);
foreach (XmlNode node in reverse)
{
Debug.WriteLine (node.Name);
}
Debug.WriteLine (reverse[0].Name);
Debug.WriteLine (reverse.Item(0 ).Name);
}