Constructing simple XML?

[Brett Romero]

What is the best way to construct this type of XML

<ROOT><Person PersonId=\"1000 \" /><Person PersonId=\"1001 \" /><Person
PersonId=\"1002 \" /></ROOT>

when I'm getting back only the three numerical values? The is occuring
in a loop and I'm getting a variable such as PersonID, which holds the
values. The XML needs to be a string but I'd like to see what a more
complex type would look like (XMLdoc type?).

Thanks,
Brett

[Brett Romero]

Re: Constructing simple XML?

This pretty much covers the creation part:
http://www.csharphelp.com/archives/archive199.html. Still not sure how
to get the two backslashes in there.

Brett

[Kai Brinkmann [MSFT]]

Re: Constructing simple XML?

Brett, you create attribute nodes just like element nodes. Here's the code
from the link you posted, modified to create the XML in your original post:

XmlDocument xmldoc;
XmlAttribute attr;
XmlElement elem;
XmlElement root;

xmldoc=new XmlDocument();

//let's add the XML declaration section
XmlNode xmlnode=xmldoc. CreateNode(XmlN odeType.XmlDecl aration,"","");
xmldoc.AppendCh ild(xmlnode);

//let's add the root element
elem=xmldoc.Cre ateElement("ROO T");
xmldoc.AppendCh ild(elem);
root = elem;

//add person elements. assume you have some data structure called ListOfIds
containing the numbers
foreach (int personId in ListOfIds)
{
elem = xmldoc.CreateEl ement("Person") ;
attr = xmldoc.CreateAt tribute("Person Id");
attr.InnerText = personId.ToStri ng();
elem.Attributes .Append(attr)
root.AppendChil d(elem);
}

--
Kai Brinkmann [MSFT]

Please do not send e-mail directly to this alias. This alias is for
newsgroup purposes only.
This posting is provided "AS IS" with no warranties, and confers no rights.


"Brett Romero" <account@cygen. com> wrote in message
news:1138227988 .559390.64060@g 14g2000cwa.goog legroups.com...[color=blue]
> This pretty much covers the creation part:
> http://www.csharphelp.com/archives/archive199.html. Still not sure how
> to get the two backslashes in there.
>
> Brett
>[/color]

[Brett Romero]

Re: Constructing simple XML?

Thanks.

If I try to read my file, which looks like this:
<?xml version="1.0"?>
<ROOT>
<Person PersonID="83615 ">
</Person>
</ROOT>

I get this error:
"The data at the root level is invalid. Line 1, position 1."

I'm using:
xmlDoc.LoadXml( @"C:\Documen ts and Settings\BROMER O\My
Documents\testi ng.spec");

I'm not sure if it is referring to the LoadXML method or the file. Any
ideas?

The <?xml version="1.0"?> part was generated with the XMLDeclaration
enumerator.

Thanks,
Brett

[Mark R. Dawson]

Re: Constructing simple XML?

Hi Brett,
the LoadXML method assumes the string you are passing as a parameter is
XML, not a file path. If you want to load XML from a file use the
XmlDocument.Loa d method and pass in the file name.

Hope that helps
Mark Dawson

http://www.markdawson.org

"Brett Romero" wrote:
[color=blue]
> Thanks.
>
> If I try to read my file, which looks like this:
> <?xml version="1.0"?>
> <ROOT>
> <Person PersonID="83615 ">
> </Person>
> </ROOT>
>
> I get this error:
> "The data at the root level is invalid. Line 1, position 1."
>
> I'm using:
> xmlDoc.LoadXml( @"C:\Documen ts and Settings\BROMER O\My
> Documents\testi ng.spec");
>
> I'm not sure if it is referring to the LoadXML method or the file. Any
> ideas?
>
> The <?xml version="1.0"?> part was generated with the XMLDeclaration
> enumerator.
>
> Thanks,
> Brett
>
>[/color]

[Anders Borum]

Re: Constructing simple XML?

For really quick XML construction, I suggest looking at the XmlWriter class
(and its descending implementations ).

--
Venlig hilsen
Anders Borum / SphereWorks
Microsoft Certified Professional (.NET MCP)