Help with DataGridTableStyle?

[Brett Romero]

I have the following DataGridTableSt yle:

DataGridTableSt yle gridTableStyle = new DataGridTableSt yle();
gridTableStyle. MappingName = "myStyle";
DataGridTextBox Column dgsc = new DataGridTextBox Column();
dgsc.MappingNam e = "FirstName" ;
dgsc.HeaderText = "First Name";
dgsc.Width = 30;
dgsc.TextBox.En abled = false;
gridTableStyle. GridColumnStyle s.Add(dgsc);

mygrid.TableSty les.Add(gridTab leStyle);
mygrid.DataSour ce = someDataView;

I can see in the grid for the assigned table that the firstname column
is "FirstName" . That should match. Instead, every row from the
DataSet shows in the grid. Shouldn't only the firstname column
display? What am I doing wrong?

Thanks,
Brett

[Brett Romero]

Re: Help with DataGridTableSt yle?

Actually, I just needed to change this
gridTableStyle. MappingName = "myStyle";

to the actual table name coming from the DataSource.

Brett

[Nicholas Paldino [.NET/C# MVP]]

Re: Help with DataGridTableSt yle?

Brett,

I don't think that you need to set the MappingName property on the table
style. The mapping name is for when you are binding to a specific type, not
for the name of the table, I believe.

From the documentation for the MappingName property:

To bind the DataGrid to a strongly typed array of objects, the object type
must contain public properties. To create a DataGridTableSt yle that displays
the array, set the DataGridTableSt yle.MappingName property to typename where
typename is replaced by the name of the object type. Also note that the
MappingName property is case-sensitive; the type name must be matched
exactly. See the MappingName property for an example.

Hope this helps.

--
- Nicholas Paldino [.NET/C# MVP]
- mvp@spam.guard. caspershouse.co m

"Brett Romero" <account@cygen. com> wrote in message
news:1137004759 .071339.158670@ g49g2000cwa.goo glegroups.com.. .[color=blue]
>I have the following DataGridTableSt yle:
>
> DataGridTableSt yle gridTableStyle = new DataGridTableSt yle();
> gridTableStyle. MappingName = "myStyle";
> DataGridTextBox Column dgsc = new DataGridTextBox Column();
> dgsc.MappingNam e = "FirstName" ;
> dgsc.HeaderText = "First Name";
> dgsc.Width = 30;
> dgsc.TextBox.En abled = false;
> gridTableStyle. GridColumnStyle s.Add(dgsc);
>
> mygrid.TableSty les.Add(gridTab leStyle);
> mygrid.DataSour ce = someDataView;
>
> I can see in the grid for the assigned table that the firstname column
> is "FirstName" . That should match. Instead, every row from the
> DataSet shows in the grid. Shouldn't only the firstname column
> display? What am I doing wrong?
>
> Thanks,
> Brett
>[/color]

[sChar]

Re: Help with DataGridTableSt yle?

/*You Need to Add only the required Column to a DataTable and then bind
that to the grid. */

dgsc.ColumnName = "FirstName" ;
/*Then you should add this Column to the Binding table*/
DataTable SomeDataTable = new DataTable();
SomeDataTable.C olumns.Add(dgsc );

/*then */

mygrid.DataSour ce = SomeDataTable;


HTH

[Peter Bromberg [C# MVP]]

RE: Help with DataGridTableSt yle?

Brett,
You can suppress the display of a column with (example)

ds.Tables("Prod ucts").Columns( "QuantityPerUni t").ColumnMappi ng =
MappingType.Hid den

--Peter

--
Co-founder, Eggheadcafe.com developer portal:

http://www.eggheadcafe.com

UnBlog:

http://petesbloggerama.blogspot.com

"Brett Romero" wrote:
[color=blue]
> I have the following DataGridTableSt yle:
>
> DataGridTableSt yle gridTableStyle = new DataGridTableSt yle();
> gridTableStyle. MappingName = "myStyle";
> DataGridTextBox Column dgsc = new DataGridTextBox Column();
> dgsc.MappingNam e = "FirstName" ;
> dgsc.HeaderText = "First Name";
> dgsc.Width = 30;
> dgsc.TextBox.En abled = false;
> gridTableStyle. GridColumnStyle s.Add(dgsc);
>
> mygrid.TableSty les.Add(gridTab leStyle);
> mygrid.DataSour ce = someDataView;
>
> I can see in the grid for the assigned table that the firstname column
> is "FirstName" . That should match. Instead, every row from the
> DataSet shows in the grid. Shouldn't only the firstname column
> display? What am I doing wrong?
>
> Thanks,
> Brett
>
>[/color]