OpenFileDialog Initial Directory not working

[Greg]

I'm a bit confused by this - when I set the InitialDiretory of an
OpenFileDialog to be a subfolder within the same folder as the app, the
file dialog does not initially display the folder - instead it shows
the last used folder (this persists after closing the app).

However, if I use a different path (e.g. "C:\\") then every time the
dialog is shown, it starts at the correct directory every time.

Is there something special about an app path that a file dialog doesn't
like, or is my syntax wrong???

OpenFileDialog objOpenDlg = new OpenFileDialog( );
objOpenDlg.Init ialDirectory = Application.Exe cutablePath + @"\Games\";
if (objOpenDlg.Sho wDialog() == DialogResult.OK )
{
//do some stuff here
}

It doesn't seem to make any difference whether the app is a debug or
release mode, and whether it is run from the IDE or not.

Any thoughts???

Greg.

[Truong Hong Thi]

Re: OpenFileDialog Initial Directory not working

Hi Greg,

Use Application.Sta rtupPath instead. Application.Exe cutablePath
includes the file name.

objOpenDlg.Init ialDirectory = Path.Combine(Ap plication.Start upPath,
"Games");

Regards,
Thi

[Greg]

Re: OpenFileDialog Initial Directory not working

Excellent, thanks a lot!