I want a line of code to execute only if it is in debug mode, is there a way
to do this in .Net/C#?
to do this in .Net/C#?
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Re: Debug Mode
Hello
If you want conditional compilation (i.e. the code would be included only in
the debug version of the application) use the following
#if DEBUG
// your debug code here
#else
// code for release version
#endif
If you want code to execute when a debugger is attached to the process
if(System.Diagn ostics.Debugger .IsAttached)
{
// Your code here
}
Best regards,
Sherif
"Nick K." <nick@bogus.com > wrote in message
news:#17aG08iEH A.644@tk2msftng p13.phx.gbl...[color=blue]
> I want a line of code to execute only if it is in debug mode, is there a[/color]
way[color=blue]
> to do this in .Net/C#?
>
>
>[/color]
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Re: Debug Mode
And one more:
Don't forget the System.Diagnost ics.Conditional Attribute class.
[Conditional("CO NDITION1")]
public static void Method1()
{
Debug.Write("Me thod1 - DEBUG and CONDITION1 are specified\n");
Trace.Write("Me thod1 - TRACE and CONDITION1 are specified\n");
}
--
Scott
On Thu, 26 Aug 2004 18:31:53 -0600, "Nick K." <nick@bogus.com > wrote:
[color=blue]
>I want a line of code to execute only if it is in debug mode, is there a way
>to do this in .Net/C#?
>
>[/color]
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