Question on Regex.Split

[Frank Oquendo]

I have the following code:

string pattern =
@"(\{)|(})|(\() |(\))|(\[)|(])|(\^)|(\*)|(/)|(-)|(\+)|(%)";
Regex regex = new Regex(pattern);
string input = "QTY * ESTIMATED COST + 2";
string[] tokens = regex.Split(inp ut);
for (int i = 0; i != tokens.Length; i++)
{
Console.WriteLi ne("Token {0} = {1}", i, tokens[i].Trim());
}
Console.ReadLin e();

According to the documentation on the Split function, the returned
string array will include the captures if I use capturing groups. IOW, I
should get an array containing 5 elements. Instead I'm only getting
three (QTY, ESTIMATED COST and 2). What am I doing wrong?

--
There are 10 kinds of people. Those who understand binary and those who
don't.

http://code.acadx.com

(Pull the pin to reply)

[Frank Oquendo]

Re: Question on Regex.Split

Never mind. I changed my pattern to the following and it works as
expected now.

string pattern = @"([-\+%\*\^\{}\(\)\[\]])";

--
There are 10 kinds of people. Those who understand binary and those who
don't.

http://code.acadx.com

(Pull the pin to reply)

[Brian Davis]

Re: Question on Regex.Split


Wrap the entire expression in (...) instead of each alternative:

(\{|}|\(|\)|\[|]|\^|\*|/|-|\+|%)


Brian Davis

https://www.knowdotnet.com

"Frank Oquendo" <franko@acadxpi n.com> wrote in message
news:Ot9IrqWqDH A.644@TK2MSFTNG P11.phx.gbl...[color=blue]
> I have the following code:
>
> string pattern =
> @"(\{)|(})|(\() |(\))|(\[)|(])|(\^)|(\*)|(/)|(-)|(\+)|(%)";
> Regex regex = new Regex(pattern);
> string input = "QTY * ESTIMATED COST + 2";
> string[] tokens = regex.Split(inp ut);
> for (int i = 0; i != tokens.Length; i++)
> {
> Console.WriteLi ne("Token {0} = {1}", i, tokens[i].Trim());
> }
> Console.ReadLin e();
>
> According to the documentation on the Split function, the returned
> string array will include the captures if I use capturing groups. IOW, I
> should get an array containing 5 elements. Instead I'm only getting
> three (QTY, ESTIMATED COST and 2). What am I doing wrong?
>
> --
> There are 10 kinds of people. Those who understand binary and those who
> don't.
>
> http://code.acadx.com
> (Pull the pin to reply)
>
>[/color]