problem with postback

**=?Utf-8?B?UGV0ZXIgQnJvbWJlcmcgW0MjIE1WUF0=?=** · Apr 23 '07, 06:15 PM

RE: problem with postback

Harry,
From what you have written, it *sounds* like what you want to do is a
cross-page postback. Look up the term "cross-page postback" and you will find
examples and description of how to use.
Peter

--
Site: http://www.eggheadcafe.com
UnBlog: http://petesbloggerama.blogspot.com
Short urls & more: http://ittyurl.net

"Harry" wrote:

Hi,
>
This aspx page (let's call it thispage.aspx) fetches data from a
sqldatasource, then performs several things (in code-behind) and, to
simplify, passes data from code-behind via a hiddenfield to a javascript in
the aspx file. This javascript performs things and finally send data via a
form to another database.
>
My problem is that when the page is postback (with this java-line:
document.getEle mentById("ins") .action="thispa ge.aspx"), instead of
performing the code after "If Page.IsPostBack Then", it shows the original
aspx file again.
>
Any idea what i have to change to do what i want to do?
Thanks
Harry
>
>
aspx file:
-------
<form id="form1" runat="server">
<asp:SqlDataSou rce ID="SqlDataSour ce1" runat="server"
ConnectionStrin g="Provider = ... ; Data Source =...;">
</asp:SqlDataSour ce>
<asp:HiddenFiel d ID="HiddenField 1" runat="server" />
</form>
>
<form id="ins" style="width:75 0px;background-color:Gray" method="post">
<input id="sql" name="sql" type="hidden" />
<input id="conn" name="conn" type="hidden" />
<input runat="server" id="Submit1" type="button" value="Klik hier om
te bewaren" onclick="sendto db()"/>
</form>
>
<script language="javas cript" type="text/javascript">
>
function sendtodb()
{
var nfieldout=docum ent.getElementB yId("hiddenfiel d1").value
......
......
document.getEle mentById("sql") .value=inscomm
document.getEle mentById("conn" ).value=conn
document.getEle mentById("ins") .action="thispa ge.aspx"
document.getEle mentById("ins") .submit()
return true;
</script>
>
>
code-behind
-----------
Protected Sub Page_Load(ByVal sender As Object, ByVal e As
System.EventArg s) Handles Me.Load
If Page.IsPostBack Then
Dim conn, sql
sql = Request.Form("s ql")
conn = Request.Form("c onn")
Dim oConnection As OleDbConnection
Dim sConnection As String
oConnection = New OleDbConnection ()
Dim comd As OleDbCommand
sConnection = conn
oConnection.Con nectionString = sConnection
oConnection.Ope n()
comd = New OleDbCommand(sq l, oConnection)
comd.ExecuteNon Query()
oConnection.Clo se()
else
HiddenField1.Va lue = "1"
.......
.......
end if
end sub
>
>
>

**Harry** · Apr 23 '07, 07:05 PM

Re: problem with postback

Peter, thanks for replying.

Maybe my explanation was not good, but i don't think it's cross-page
postback, since the 'action' method in javascript of the form
(document.getEl ementByI("ins") .action="thispa ge.aspx") refers to itself
("thispage.aspx "). The whole code here below is contained in "thispage.a spx"
and "thispage.aspx. vb".

"Peter Bromberg [C# MVP]" <pbromberg@yaho o.yabbadabbadoo .comschreef in
bericht news:605297C0-E8BB-4DB5-B7E8-405B98B69924@mi crosoft.com...

Harry,
From what you have written, it *sounds* like what you want to do is a
cross-page postback. Look up the term "cross-page postback" and you will
find
examples and description of how to use.
Peter
>
--
Site: http://www.eggheadcafe.com
UnBlog: http://petesbloggerama.blogspot.com
Short urls & more: http://ittyurl.net
>
>
>
>
"Harry" wrote:
>

>Hi,
>>
>This aspx page (let's call it thispage.aspx) fetches data from a
>sqldatasourc e, then performs several things (in code-behind) and, to
>simplify, passes data from code-behind via a hiddenfield to a javascript
>in
>the aspx file. This javascript performs things and finally send data via
>a
>form to another database.
>>
>My problem is that when the page is postback (with this java-line:
>document.getEl ementById("ins" ).action="thisp age.aspx"), instead of
>performing the code after "If Page.IsPostBack Then", it shows the
>original
>aspx file again.
>>
>Any idea what i have to change to do what i want to do?
>Thanks
>Harry
>>
>>
>aspx file:
>-------
> <form id="form1" runat="server">
> <asp:SqlDataSou rce ID="SqlDataSour ce1" runat="server"
>ConnectionStri ng="Provider = ... ; Data Source =...;">
></asp:SqlDataSour ce>
> <asp:HiddenFiel d ID="HiddenField 1" runat="server" />
> </form>
>>
> <form id="ins" style="width:75 0px;background-color:Gray" method="post">
> <input id="sql" name="sql" type="hidden" />
> <input id="conn" name="conn" type="hidden" />
> <input runat="server" id="Submit1" type="button" value="Klik hier
>om
>te bewaren" onclick="sendto db()"/>
> </form>
>>
><script language="javas cript" type="text/javascript">
>>
>function sendtodb()
>{
>var nfieldout=docum ent.getElementB yId("hiddenfiel d1").value
>......
>......
>document.getEl ementById("sql" ).value=inscomm
>document.getEl ementById("conn ").value=co nn
>document.getEl ementById("ins" ).action="thisp age.aspx"
>document.getEl ementById("ins" ).submit()
>return true;
></script>
>>
>>
>code-behind
>-----------
> Protected Sub Page_Load(ByVal sender As Object, ByVal e As
>System.EventAr gs) Handles Me.Load
>If Page.IsPostBack Then
> Dim conn, sql
> sql = Request.Form("s ql")
> conn = Request.Form("c onn")
> Dim oConnection As OleDbConnection
> Dim sConnection As String
> oConnection = New OleDbConnection ()
> Dim comd As OleDbCommand
> sConnection = conn
> oConnection.Con nectionString = sConnection
> oConnection.Ope n()
> comd = New OleDbCommand(sq l, oConnection)
> comd.ExecuteNon Query()
> oConnection.Clo se()
>else
>HiddenField1.V alue = "1"
>.......
>.......
>end if
>end sub
>>
>>
>>

**bruce barker** · Apr 23 '07, 08:25 PM

Re: problem with postback

IsPostBack just checks for the "__Viewstat e" hidden field in the
postback form fields. as you are submitting a different form on the page
then the one containing the viewstate, the viewstate hidden field is not
included in the postback data

-- bruce (sqlwork.com)

Harry wrote:

Peter, thanks for replying.
>
Maybe my explanation was not good, but i don't think it's cross-page
postback, since the 'action' method in javascript of the form
(document.getEl ementByI("ins") .action="thispa ge.aspx") refers to itself
("thispage.aspx "). The whole code here below is contained in "thispage.a spx"
and "thispage.aspx. vb".
>
>
"Peter Bromberg [C# MVP]" <pbromberg@yaho o.yabbadabbadoo .comschreef in
bericht news:605297C0-E8BB-4DB5-B7E8-405B98B69924@mi crosoft.com...

>Harry,
>From what you have written, it *sounds* like what you want to do is a
>cross-page postback. Look up the term "cross-page postback" and you will
>find
>examples and description of how to use.
>Peter
>>
>--
>Site: http://www.eggheadcafe.com
>UnBlog: http://petesbloggerama.blogspot.com
>Short urls & more: http://ittyurl.net
>>
>>
>>
>>
>"Harry" wrote:
>>

>>Hi,
>>>
>>This aspx page (let's call it thispage.aspx) fetches data from a
>>sqldatasource , then performs several things (in code-behind) and, to
>>simplify, passes data from code-behind via a hiddenfield to a javascript
>>in
>>the aspx file. This javascript performs things and finally send data via
>>a
>>form to another database.
>>>
>>My problem is that when the page is postback (with this java-line:
>>document.getE lementById("ins ").action="this page.aspx"), instead of
>>performing the code after "If Page.IsPostBack Then", it shows the
>>original
>>aspx file again.
>>>
>>Any idea what i have to change to do what i want to do?
>>Thanks
>>Harry
>>>
>>>
>>aspx file:
>>-------
>> <form id="form1" runat="server">
>> <asp:SqlDataSou rce ID="SqlDataSour ce1" runat="server"
>>ConnectionStr ing="Provider = ... ; Data Source =...;">
>></asp:SqlDataSour ce>
>> <asp:HiddenFiel d ID="HiddenField 1" runat="server" />
>> </form>
>>>
>> <form id="ins" style="width:75 0px;background-color:Gray" method="post">
>> <input id="sql" name="sql" type="hidden" />
>> <input id="conn" name="conn" type="hidden" />
>> <input runat="server" id="Submit1" type="button" value="Klik hier
>>om
>>te bewaren" onclick="sendto db()"/>
>> </form>
>>>
>><script language="javas cript" type="text/javascript">
>>>
>>function sendtodb()
>>{
>>var nfieldout=docum ent.getElementB yId("hiddenfiel d1").value
>>......
>>......
>>document.getE lementById("sql ").value=inscom m
>>document.getE lementById("con n").value=co nn
>>document.getE lementById("ins ").action="this page.aspx"
>>document.getE lementById("ins ").submit()
>>return true;
>></script>
>>>
>>>
>>code-behind
>>-----------
>> Protected Sub Page_Load(ByVal sender As Object, ByVal e As
>>System.EventA rgs) Handles Me.Load
>>If Page.IsPostBack Then
>> Dim conn, sql
>> sql = Request.Form("s ql")
>> conn = Request.Form("c onn")
>> Dim oConnection As OleDbConnection
>> Dim sConnection As String
>> oConnection = New OleDbConnection ()
>> Dim comd As OleDbCommand
>> sConnection = conn
>> oConnection.Con nectionString = sConnection
>> oConnection.Ope n()
>> comd = New OleDbCommand(sq l, oConnection)
>> comd.ExecuteNon Query()
>> oConnection.Clo se()
>>else
>>HiddenField1. Value = "1"
>>.......
>>.......
>>end if
>>end sub
>>>
>>>
>>>

>
>

**Harry** · Apr 24 '07, 08:05 AM

Re: problem with postback

Thanks for the explanation.
Now, if you would have a solution in mind for that, it would be great.

"bruce barker" <nospam@nospam. comschreef in bericht
news:%23g4bzSeh HHA.4936@TK2MSF TNGP04.phx.gbl. ..

IsPostBack just checks for the "__Viewstat e" hidden field in the postback
form fields. as you are submitting a different form on the page then the
one containing the viewstate, the viewstate hidden field is not included
in the postback data
>
>
-- bruce (sqlwork.com)
>
Harry wrote:

>Peter, thanks for replying.
>>
>Maybe my explanation was not good, but i don't think it's cross-page
>postback, since the 'action' method in javascript of the form
>(document.getE lementByI("ins" ).action="thisp age.aspx") refers to itself
>("thispage.asp x"). The whole code here below is contained in
>"thispage.aspx " and "thispage.aspx. vb".
>>
>>
>"Peter Bromberg [C# MVP]" <pbromberg@yaho o.yabbadabbadoo .comschreef in
>bericht news:605297C0-E8BB-4DB5-B7E8-405B98B69924@mi crosoft.com...

>>Harry,
>>From what you have written, it *sounds* like what you want to do is a
>>cross-page postback. Look up the term "cross-page postback" and you will
>>find
>>examples and description of how to use.
>>Peter
>>>
>>--
>>Site: http://www.eggheadcafe.com
>>UnBlog: http://petesbloggerama.blogspot.com
>>Short urls & more: http://ittyurl.net
>>>
>>>
>>>
>>>
>>"Harry" wrote:
>>>
>>>Hi,
>>>>
>>>This aspx page (let's call it thispage.aspx) fetches data from a
>>>sqldatasourc e, then performs several things (in code-behind) and, to
>>>simplify, passes data from code-behind via a hiddenfield to a
>>>javascript in
>>>the aspx file. This javascript performs things and finally send data
>>>via a
>>>form to another database.
>>>>
>>>My problem is that when the page is postback (with this java-line:
>>>document.get ElementById("in s").action="thi spage.aspx"), instead of
>>>performing the code after "If Page.IsPostBack Then", it shows the
>>>original
>>>aspx file again.
>>>>
>>>Any idea what i have to change to do what i want to do?
>>>Thanks
>>>Harry
>>>>
>>>>
>>>aspx file:
>>>-------
>>> <form id="form1" runat="server">
>>> <asp:SqlDataSou rce ID="SqlDataSour ce1" runat="server"
>>>ConnectionSt ring="Provider = ... ; Data Source =...;">
>>></asp:SqlDataSour ce>
>>> <asp:HiddenFiel d ID="HiddenField 1" runat="server" />
>>> </form>
>>>>
>>> <form id="ins" style="width:75 0px;background-color:Gray"
>>>method="post ">
>>> <input id="sql" name="sql" type="hidden" />
>>> <input id="conn" name="conn" type="hidden" />
>>> <input runat="server" id="Submit1" type="button" value="Klik hier
>>>om
>>>te bewaren" onclick="sendto db()"/>
>>> </form>
>>>>
>>><script language="javas cript" type="text/javascript">
>>>>
>>>function sendtodb()
>>>{
>>>var nfieldout=docum ent.getElementB yId("hiddenfiel d1").value
>>>......
>>>......
>>>document.get ElementById("sq l").value=insco mm
>>>document.get ElementById("co nn").value=co nn
>>>document.get ElementById("in s").action="thi spage.aspx"
>>>document.get ElementById("in s").submit()
>>>return true;
>>></script>
>>>>
>>>>
>>>code-behind
>>>-----------
>>> Protected Sub Page_Load(ByVal sender As Object, ByVal e As
>>>System.Event Args) Handles Me.Load
>>>If Page.IsPostBack Then
>>> Dim conn, sql
>>> sql = Request.Form("s ql")
>>> conn = Request.Form("c onn")
>>> Dim oConnection As OleDbConnection
>>> Dim sConnection As String
>>> oConnection = New OleDbConnection ()
>>> Dim comd As OleDbCommand
>>> sConnection = conn
>>> oConnection.Con nectionString = sConnection
>>> oConnection.Ope n()
>>> comd = New OleDbCommand(sq l, oConnection)
>>> comd.ExecuteNon Query()
>>> oConnection.Clo se()
>>>else
>>>HiddenField1 .Value = "1"
>>>.......
>>>.......
>>>end if
>>>end sub
>>>>
>>>>
>>>>

>>

problem with postback

problem with postback

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