finding the antinodes on a waveform

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  • tristancohn
    New Member
    • Sep 2013
    • 1

    finding the antinodes on a waveform

    i have a waveform:
    y2(x)= sin(x*1.2)+sin( x*1.8 )

    the first 6 nodes, meaning the parts of the wave where y2=0 come up on my graph at around x =

    2.094
    4.189
    5.236
    6.283
    8.377
    10.471

    you can find the nodes easily (where y2=0) with either x = n*pi/(1.5) or x = (2n+1)*(pi/0.6), where n = 0, 1,2 3, and so on.

    what I really want to find is the antinodes (peaks) of y2, similar to on this graph where the line turns black:

    http://upload.wikimedi a.org/wikipedi...ativ e_line.gif

    which are at around x =

    1.006
    2.979
    4.665
    5.808
    7.492
    9.466

    I know that the antinodes for y2 come up at 1.8*COS(1.8*x)+ 1.2*COS(1.2*x)= 0
    but i just can't find a clean way of finding them.
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