Method 'Items' of object "Forms" failed

[svdoerga]

I found a post with the same error here.
I'm getting the same error. This code is run in a button click event:

...........
DoCmd.OpenForm CurTabViewName, acNormal
With Forms(CurTabViewName) 
...........

At the "With" statement I get the error. Weird thing is this code had been working fine a long time. I've been searching the net and haven't been able to find the solution yet. Does anyone know a solution?

Only possibility I found out (from the above linked post) is that maybe it has to do with timing. I can imagine that the form is not completely ready when the "with" statement executes. Is there any way to tell access to wait until the form is completely loaded before executing the "with" statement?

[hyperpau]

have you tried putting a refresh, repaint, or recalc method in betweene these codes?

[missinglinq]

Access executes Command2 without waiting for Command1 to finish executing, which can, indeed, cause timing problems. In this case, my guess is that the form hasn't finished loading/opening when the next line of code tries to reference it.

Refresh, repaint, or recalc is going to do nothing to correct this. What does frequently help is to place the command DoEvents between two commands.
DoEvents basically sends control from Access to Windows to allow Command1 to finish before returning control to Access to execute Command2.

Welcome to Bytes!

Linq ;0)>

[hyperpau]

Wow. That's new for me! :)

Thanks Missingling.

Access executes Command2 without waiting for Command1 to finish executing, which can, indeed, cause timing problems. In this case, my guess is that the form hasn't finished loading/opening when the next line of code tries to reference it.

Refresh, repaint, or recalc is going to do nothing to correct this. What does frequently help is to place the command DoEvents between two commands.
DoEvents basically sends control from Access to Windows to allow Command1 to finish before returning control to Access to execute Command2.

Welcome to Bytes!

Linq ;0)>