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The problem with this code is that there are no errors showing, but when i compile the program, the if else statements do not carry out as they should do. Both if statements show the same answer, for example the second if statement. If I type Y or N then I get the same thing, 'You will now choose an event'. How do i get rid of this problem? Is char supposed to be used or string?
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Hi,

I have developed a search tool using PHP. The uses what's typed into a search box to replace part of a URL.

I am wondering if anyone can help me add IF statements to this function.

The user can search for ISBN numbers, which have to be 10 characters long. I would like a feature that tells them this if they don't type in a valid ISBN number.

I don't think this is possible, but is there...

Hello,
I'm working on a search form. I have 3 combo boxes and I want to find combinations on a query to later show it in a report. Perhaps this is too complicated but I don't know how else to do it. I thought this code worked at first, but then a realized it wasn't really working. I know something is up with the if statements but I don't know how to fix it.

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I've read countless times, and in fact used it correctly, that you can use boolean logic in an if statement to test whether a string is equal to another string, although my compiler (visual studio 2005) just skips over this particular if statement.
this is a snippet of the code:

printf("Encrypt : file encryption program. Type h for help.");
do
{
printf("\n>> ");
fgets(init,...

Hello all. So i have a question about searching strings. I have the following if statement...

if (parser.get_tok en(i,2).at(0) =='#' && parser.get_toke n(i,2).at(1)==' 5'){
...
...
..
}

What I want to do is change where it says "=='5' " to be able to look for all numbers 0-9 instead of just 5. Any help would be awesome. Thanks.