can't get rid of xmlns attribute

[Dormilich]

Hi,

I have some problems removing the xmlns attributes from a transformed xml file. I can't completely remove them (so it would validate).

the problematic elements are <div> or the elements pasted by <xsl:copy-of>

if I have no default NS in the XSL file I get the namespace attribute attached to the copied elements (the one from the "plan" prefix because that's default NS of the XML, all prefixed NS are removed).

if I have a default NS in the XSL file, the copied elements are free of NS, but the NS is now attached to the <div> element (because it's the top level element in the result XML).

so, how do I need to change my copy construct to get all elements without NS?

alternatively I have to add a preg_replace() function to my script, if this is not possible with XSL......

the xsl file (the important part):

<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:plan="urn:kbl.plan:current-and-bygone-playlists" // default NS of the XML file
    exclude-result-prefixes="xsl plan">

[...]

<xsl:template match="/">
  <xsl:element name="div">  // either I have xmlns="..." here ...
    <xsl:attribute name="class">
      <xsl:text>mitte inhalt</xsl:text>
    </xsl:attribute>
[...]
    <xsl:for-each select="$basis/child::plan:thema">
      <xsl:call-template name="themen" />
    </xsl:for-each>
  </xsl:element>
</xsl:template>

<xsl:template name="themen">
  <xsl:call-template name="balken" />
  <xsl:for-each select="plan:termin">
    <xsl:call-template name="termine" />
  </xsl:for-each>
  <xsl:if test="plan:xhtml">
    <xsl:copy-of select="plan:xhtml/*" /> // ... or here
  </xsl:if>
</xsl:template>

[jkmyoung]

Have you tried using a seperate copy template?
[code=xml]
<xsl:template name="copy">
<xsl:element name="local-name()">
<xsl:copy-of select="@*"/>
<xsl:for-each select="*">
<xsl:call-template name="copy"/>
</xsl:for-each>
</xsl:element>
</xsl:template>

Change
<xsl:copy-of select="plan:xh tml/*" />
with
<xsl:for-each select="plan:xh tml/*">
<xsl:call-template name="copy"/>
</xsl:for-each>
[/code]

[Dormilich]

Have you tried using a seperate copy template?

admittedly you are much better with such copy problems than I am. I'll try it.

regards

[Dormilich]

tried the template but I got a problem. the XSLT returns with an error (i.e. the XSLTProcessor:: transformToXml( ) method returns false. I could narrow down the problem to the following:

<xsl:template name="copy">
// if I use this line I get the error
  [B]<xsl:element name="local-name()">[/B]
    <xsl:copy-of select="@*"/>
    <xsl:for-each select="*">
      <xsl:call-template name="copy"/>
    </xsl:for-each>
 [B] </xsl:element>[/B]
</xsl:template>

I have no idea, why it does so.....

[Dormilich]

finally solved the problem, looked like the name attribute doesn't accept every input. nevertheless, thank you jkmyoung!
[CODE=xml]<xsl:template name="copy">
<xsl:element name="{local-name()}">
<xsl:copy-of select="@*"/>
<xsl:value-of select="text()"/>
<xsl:for-each select="plan:*" >
<xsl:call-template name="copy"/>
</xsl:for-each>
</xsl:element>
</xsl:template>[/CODE]

[jkmyoung]

Sorry, forgot that attribute was a string, not an xpath. But you figured out the braces so it's ok.

[Dormilich]

But you figured out the braces so it's ok.

it was rather a lucky guess....