Converting HTML tags within an XML document back to HTML using XSL

[Izhaki]

Hi,

I'm creating a system where my XML includes HTML tags (<h1></h1>) in addition to other XML elements (<book></book>).

I would like to render the HTML tags back to HTML using XSL. Considering I want to replace all headings, I could do for each heading level (i.e. repeat the following code for h2, h3, h4, h5, etc.):

<xsl:template match="h1">
<h1><xsl:appl y-templates/></h1>
</xsl:template>

or I can just write once:

<xsl:template match="*[starts-with(local-name(), 'h')]">
<xsl:copy><xsl: apply-templates/></xsl:copy>
</xsl:template>

The problem is that with xsl:copy, I'm loosing the 'native' HTML appearance of the tags. For example, the headings will be displayed inline rather than block. To solve this I can just edit the stylesheet and add display:block to all headings - meaning I'm doing extra job anyway, but I was wondering if there is any smart way of doing this.

Ideally, I would like to do something like this:

<xsl:template match="p|ul|li| dl|dt|dd|i|em|s trong|b">
<xsl:copy><xsl: apply-templates/></xsl:copy>
</xsl:template>

rather than writing each separately.

Thanks in advance,
Izhaki

[jkmyoung]

Are you missing copying the attributes?
Guessing something like:
[code=xml]
<xsl:template match="h1|h2|h3 |h4|h5">
<h1>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</h1>
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
[/code]