The VB6's INT function has a strange behavior

[Loche]

Dim iContatore As Integer
Dim nCifre As Integer

iContatore = 10
nCifre = Int(Log(iContat ore) / Log(10))
Debug.Print nCifre

It gives me '0' instead of '1'. WHY??

[iam_clint]

What's your log function look like?

[Loche]

Log(iContatore) gives me 1 and also Log(10). So if I write
nCifre=Log(iCon tatore)/Log(10) I get 1!

[Rabbit]

That's not right. The log function uses e as the base. So Log(10) returns 2.3025850929940 456840179914546 844.... So what you have is a float divided by a float. The problem with float division is that it is not precise. The answer you get when dividing it will be somewhere between slightly less than 1 and slightly more than one. In your case, it is returning slightly less than one so when that is converted to an integer, it comes out to zero.

[Loche]

Sorry Rabbit, you are right: vb6's Log function uses e base!
Thank you for the answer, but is there a way to get the right result?

[Rabbit]

Round the result to the decimal precision you need for other calculations you might need to do.

[Loche]

Thank you very much.