IsNumeric()

[mwcapps]

So I'm passing a masked telephone number in the form of (999)999-9999 to a Function that 'strips' the numbers out and puts them into a string that I then use in an Update SQL statement. So far I have the code below that of course doesn't do anything:

Function StripPhone(ByVa l sPhone as String) as String
Dim i as Integer
Dim sStripped as String

For i = 1 to Len(sPhone)
If IsNumeric(Mid(s Phone, i)) Then
sStripped = i
sStripped = sStripped & Mid(sPhone, i)
End if
i = i + 1
Next
StripPhone = sStripped
End Function

[MrMancunian]

So what's your question here?

Steven

[mwcapps]

My question is: How do I test the data to see if the characters are numbers? And how do I add them to a string if they are?

[MrMancunian]

You were pretty close. This is the correct code:

Function StripPhone(ByVal sPhone As String) As String
  Dim i As Integer
  Dim sStripped As String = ""
  For i = 1 To Len(sPhone)
    If IsNumeric(Mid(sPhone, i, 1)) Then
      sStripped = sStripped & Mid(sPhone, i, 1)
    End If
  Next
  Return sStripped
End Function

The For-Next-loop already increases i, so you didn't have to do that. sStripped = i doesn't make sense, as you don't want it to be the counter, but a part of the string. Further, Mid is used as Mid(string, start, length). This way, it is crystal clear which part of the string you want to check.

Steven

[mwcapps]

Mr. Steve,

Thank you sooo much. That worked, which I'm sure you're not surprised. You solved in an hour what I've been working on for 3 weeks. Thanks again for your help.

[aryanbs]

Mr. Steve,

Thank you sooo much. That worked, which I'm sure you're not surprised. You solved in an hour what I've been working on for 3 weeks. Thanks again for your help.

I am surprised how do you know it took him an hour?

[aryanbs]

And One more thing, If its a MaskedTextBox then there is a property called
TextMaskFormat, setting it to ExcludePromptAn dLiterals gives the text only from its text property.