Query/View: The 2 newest periods for each indicator

[Ryan Dahl]

Hi,

I'm working on a simple performance-program, where I need to extract
information from the 2 newest periods for every performance-indicator
- And from there calculate a trend between these results.

The problem is, that I can't find a simple way to extract the 2 latest
results.

The Table (Table1) looks like this:
kpiID periodID Actual
Acceleration 2 3
Acceleration 5 4
Speed 1 100
Speed 4 200
Speed 7 220
Speed 9 180
Weight 1 22
Weight 3 32
Weight 7 21
Weight 10 33

If I want to extract the newest I use something like this (made it in
MS Access, so the syntax might differ slightly from SQLServer):

SELECT table1.kpiID, table1.periodID , table1.Actual
FROM table1 WHERE table1.periodID = (SELECT max(t.periodID) from
table1 as t WHERE t.kpiID=table1. kpiID);

BUT - how how do I get the second-newest period as well?

Preferably I would like the final result to be a View with the
following fields:
kpiID, periodID_newest , Actual_newest, periodID_sec_ne west,
Actual_sec_newe st

Alternatively a View with 2 posts for each performace-indicator.

Thanks in advance
Ryan

[Hugo Kornelis]

Re: Query/View: The 2 newest periods for each indicator

On Fri, 24 Mar 2006 23:08:18 +0100, Ryan Dahl wrote:
[color=blue]
>Hi,
>
>I'm working on a simple performance-program, where I need to extract
>information from the 2 newest periods for every performance-indicator
>- And from there calculate a trend between these results.
>
>The problem is, that I can't find a simple way to extract the 2 latest
>results.
>
>The Table (Table1) looks like this:
>kpiID periodID Actual
>Acceleration 2 3
>Acceleration 5 4
>Speed 1 100
>Speed 4 200
>Speed 7 220
>Speed 9 180
>Weight 1 22
>Weight 3 32
>Weight 7 21
>Weight 10 33
>
>If I want to extract the newest I use something like this (made it in
>MS Access, so the syntax might differ slightly from SQLServer):
>
>SELECT table1.kpiID, table1.periodID , table1.Actual
>FROM table1 WHERE table1.periodID = (SELECT max(t.periodID) from
>table1 as t WHERE t.kpiID=table1. kpiID);
>
>BUT - how how do I get the second-newest period as well?[/color]

Hi Ryan,

SELECT a.kpiID, a.periodID, a.Actual
FROM table1 AS a
WHERE (SELECT COUNT(*)
FROM table1 AS b
WHERE b.kpiID = a.kpiID
AND b.periodID >= a.periodID) <= 2
[color=blue]
>
>Preferably I would like the final result to be a View with the
>following fields:
>kpiID, periodID_newest , Actual_newest, periodID_sec_ne west,
>Actual_sec_new est[/color]

In that case, try this instead:

SELECT a.kpiID, a.periodID, a.Actual, b.periodID, b.Actual
FROM table1 AS a
LEFT JOIN table1 AS b
ON b.kpiID = a.kpiID
AND b.periodID = (SELECT MAX(c.periodID)
FROM table1 AS c
WHERE c.kpiID = a.kpiID
AND c.periodID < a.periodID)
WHERE a.periodID = (SELECT MAX(t.periodID)
FROM table1 AS t
WHERE t.kpiID = a.kpiID)

(Both queries above are untested - see www.aspfaq.com/5006 if you prefer
a tested reply).

--
Hugo Kornelis, SQL Server MVP

[Ryan Dahl]

Re: Query/View: The 2 newest periods for each indicator

Hi Hugo,

Thanks a lot. I got them both working without any hassle.
[color=blue]
>SELECT a.kpiID, a.periodID, a.Actual
>FROM table1 AS a
>WHERE (SELECT COUNT(*)
> FROM table1 AS b
> WHERE b.kpiID = a.kpiID
> AND b.periodID >= a.periodID) <= 2[/color]

I find this to be quite clever - had to look at it some time to figure
out how it works.
[color=blue][color=green]
>>
>>Preferably I would like the final result to be a View with the
>>following fields:
>>kpiID, periodID_newest , Actual_newest, periodID_sec_ne west,
>>Actual_sec_ne west[/color]
>
>In that case, try this instead:
>
>SELECT a.kpiID, a.periodID, a.Actual, b.periodID, b.Actual
>FROM table1 AS a
>LEFT JOIN table1 AS b
> ON b.kpiID = a.kpiID
> AND b.periodID = (SELECT MAX(c.periodID)
> FROM table1 AS c
> WHERE c.kpiID = a.kpiID
> AND c.periodID < a.periodID)
>WHERE a.periodID = (SELECT MAX(t.periodID)
> FROM table1 AS t
> WHERE t.kpiID = a.kpiID)
>[/color]
Works as well - minor adjustment needed: Move lines 5-8 to the end.

Regards
Ryan

[--CELKO--]

Re: Query/View: The 2 newest periods for each indicator

Please post DDL, so that people do not have to guess what the keys,
constraints, Declarative Referential Integrity, data types, etc. in
your schema are. Sample data is also a good idea, along with clear
specifications.

I am a little confused on this. Aren't "accelerati on", "speed", and
"weight" attributes and not values? Surely you are not mixing
meteadata and data.

[Doug]

Re: Query/View: The 2 newest periods for each indicator

celko, have you actually ever HELPED anyone on this list?????

i'd be curious to review a link where your original SQL code, written
in the past 10 years, is deomonstrated.

thx,
doug

[Hugo Kornelis]

Re: Query/View: The 2 newest periods for each indicator

On Sat, 25 Mar 2006 08:21:38 +0100, Ryan Dahl wrote:
[color=blue][color=green]
>>SELECT a.kpiID, a.periodID, a.Actual, b.periodID, b.Actual
>>FROM table1 AS a
>>LEFT JOIN table1 AS b
>> ON b.kpiID = a.kpiID
>> AND b.periodID = (SELECT MAX(c.periodID)
>> FROM table1 AS c
>> WHERE c.kpiID = a.kpiID
>> AND c.periodID < a.periodID)
>>WHERE a.periodID = (SELECT MAX(t.periodID)
>> FROM table1 AS t
>> WHERE t.kpiID = a.kpiID)
>>[/color]
>Works as well - minor adjustment needed: Move lines 5-8 to the end.[/color]

Hi Ryan,

That changes the meaning of the query - the place where you put those
lines dictates what will happen for a kpiID that has only one row.

This one row is by definition the latest - but there's no second latest.
If you use the query I suggested, you'll get this kpiID in your result,
with it's only row as last measurement and NULLs as it's second latest
measurement.

Your version (after moving those rows) will exclude any kpiID with only
one row. Only kpiIDs with two or more measurements will be displayed. If
that is indeed your requirement, then you can safely move these lines.
And you can change the LEFT JOIN in an INNER JOIN as well, to get some
performance gain.

--
Hugo Kornelis, SQL Server MVP

[Ryan Dahl]

Re: Query/View: The 2 newest periods for each indicator

On Mon, 27 Mar 2006 23:48:50 +0200, Hugo Kornelis
<hugo@perFact.R EMOVETHIS.info. INVALID> wrote:
[color=blue]
>On Sat, 25 Mar 2006 08:21:38 +0100, Ryan Dahl wrote:
>[color=green][color=darkred]
>>>SELECT a.kpiID, a.periodID, a.Actual, b.periodID, b.Actual
>>>FROM table1 AS a
>>>LEFT JOIN table1 AS b
>>> ON b.kpiID = a.kpiID
>>> AND b.periodID = (SELECT MAX(c.periodID)
>>> FROM table1 AS c
>>> WHERE c.kpiID = a.kpiID
>>> AND c.periodID < a.periodID)
>>>WHERE a.periodID = (SELECT MAX(t.periodID)
>>> FROM table1 AS t
>>> WHERE t.kpiID = a.kpiID)
>>>[/color]
>>Works as well - minor adjustment needed: Move lines 5-8 to the end.[/color]
>
>Hi Ryan,
>
>That changes the meaning of the query - the place where you put those
>lines dictates what will happen for a kpiID that has only one row.
>
>This one row is by definition the latest - but there's no second latest.
>If you use the query I suggested, you'll get this kpiID in your result,
>with it's only row as last measurement and NULLs as it's second latest
>measurement.
>
>Your version (after moving those rows) will exclude any kpiID with only
>one row. Only kpiIDs with two or more measurements will be displayed. If
>that is indeed your requirement, then you can safely move these lines.
>And you can change the LEFT JOIN in an INNER JOIN as well, to get some
>performance gain.[/color]

Hi Hugo,

thanks for pointing this out. SQLServer accepted without any problems.
As mentioned earlier I tested on MS Access, and it seems that it
doesn't support this join-type (no error-description of any kind) so I
made the mistake of assuming there was a small error in the
sql-string.

Thanks again.
Ryan

[qtuner@gmail.com]

Re: Query/View: The 2 newest periods for each indicator

I've read 2 books written by joe celko, and and both have really helped
me. I frequently profile my code to see what it is doing. So he's
helped me.

[--CELKO--]

Re: Query/View: The 2 newest periods for each indicator

Go to the CMP archives for DBMS, DATABASE PROGRAMMING & DESIGN, and
INTELLIGENT ENTERPRISE magazines to go back over ten years. I have
written over 750 columns in the computer trade and academic press,
mostly dealing with data and databases. I currently write for BMC's
DBAzine.com e-magazine.

My six books: SQL FOR SMARTIES (Morgan-Kaufmann, 1995, second edition
1999, third edition 2005), SQL PUZZLES & ANSWERS (Morgan-Kaufmann,
1997), DATA & DATABASES (Morgan-Kaufmann, 1999) and TREES & HIERARCHIES
IN SQL (Morgan-Kaufmann, 2004) and SQL PROGRAMMING STYLE
Morgan-Kaufmann, 2005).
Past magazine columns include: "SQL Explorer" in DBMS (Miller-Freeman);
"Celko on SQL" in DATABASE PROGRAMMING & DESIGN (Miller-Freeman);
"WATCOM SQL Corner" in POWERBUILDER DEVELOPERS' JOURNAL (SysCon); "SQL
Puzzle" in BOXES & ARROWS (Frank Sweet Publishing); "DBMS/Report" in
SYSTEMS INTEGRATION (Cahner-Ziff); "Data Desk" in TECH SPECIALIST
(R&D); "Data Points" in PC TECHNIQUES (Coriolis Group); "Celko on
Software" in COMPUTING (VNC Publications, UK), "SELECT * FROM Austin"
(Array Publications, The Netherlands), and he was editor for the
"Puzzles & Problems" section of ABACUS (Springer-Verlag) and I ran the
CASEFORUM section 18, "Celko on SQL", on CompuServe.

So, what have you done?

[Alexander Kuznetsov]

Re: Query/View: The 2 newest periods for each indicator

if it is SQL Server 2005, use row_number() *untested*:

select * from(
SELECT table1.kpiID, table1.periodID , table1.Actual,
row_number() over(partition by kpId order by periodId desc) rn
FROM table1
) t
where rn<3

[GeorgeM]

Re: Query/View: The 2 newest periods for each indicator

That's Joe Celko, the demi-god of SQL for pete's sake.