How to reverse a list for the purpose of finding the previous item with a condition ?

[amskape]

Dear friends,
I try to find the forward and backward content of a play list . The main item is identified using <h1> tag ...
I wrote a code for forward item which works fine as below:

    if(direction == "forward"):
	counter = 0
	for i in range(self.pos_indice,len(self.indice)):
	    if(self.indice[i+1].tagName == "h1"):
	       break
	    else:
	       counter = counter+1
	return counter+1

but in reverse my code fails as shown below:

if(direction == "backword"):
	rev_counter = self.pos_indice
	for j in range(self.pos_indice,0,-1):
	    if(self.indice[j+1].tagName == "h1"):
	       break
	    else:
	       rev_counter = rev_counter + 1
	return rev_counter+1

Please advise with a solution fast

Thanks
Anes

[Luk3r]

Python has a built-in reversed() function which can be used in a For loop.

[amskape]

Dear Luk3r,
I used following code for purpose and feel works fine 90% !!

    if(direction == "backword"):
	rev_counter = 0
	for j in range(self.pos_indice,-1,-1):
	    
	    if(self.indice[j-1].tagName == "h1"):
	       break
	    else:
	       rev_counter = rev_counter + 1
	return rev_counter+1

Please advise any further modifications.. ..

Thanks
Anes