jython code

[spgreddy]

Hi,

When I execute below program I am getting the below output.

for row in c.fetchall():
        urls=row
        print urls

('http://10.136.229.129: 7010',)
('http://10.136.229.129: 7020',)
('http://10.136.229.129: 7030',)
('http://10.136.229.129: 7040',)
('http://10.136.229.44:7 050',)
('http://10.136.229.44:7 060',)
('http://10.136.229.44:7 070',)
('http://10.136.229.44:7 080',)


but I want to get below output

http://10.136.229.129:7010

http://10.136.229.129:7020

http://10.136.229.129:7030

http://10.136.229.129:7040

http://10.136.229.44:7050

http://10.136.229.44:7060

http://10.136.229.44:7070

http://10.136.229.44:7080

Please let me know how can I achieve this by either python or jython script

Regards
spgreddy

[bvdet]

c.fetchall() returns a list of tuples. To cover the possibility of an empty tuple or tuple with multiple entries:

print "\n".join([",".join(item) for item in c.fetchall()])