how to return the characters in string "s" in outermost pair of matching quotes

[dragonwolf]

suppose we have to return the charccters in string "s" which are contained in the outermost pair of matching quotes and return nothing when there are no quotes

 c = s.find('""')
    if c != -1:
        for item in s:
            if c < len(z) -1 :
                if c[k+1] == '""':
                    return char
                else:
                    char = char + s[k+1]
                    c = c+ 1
                    return char

this is my code but its not working,can any one help me out
thanks

[dwblas]

Not from what you posted
1. "s" is not defined
2. there is at least one indentation error
3. there is a problem with at least one return
4. "z" had not been declared
5. "k" had not been declared
6. "char" had not been declared
7. what happens if '""' is not found

If anyone falls for the old post-gobbledygook-to-get-someone-to-do-your-homework-for-you, then they are not someone you want to take advice from, and if that is what this is, please don't waste our time.