[urllib2] No time-out?

[Gilles Ganault]

Hello

I'm using urllib2 to download web pages. The strange thing in the code
below, is that it seems like urllib2.urlopen retries indefinitely by
itself instead of raising an exception:

=====
timeout = 30
socket.setdefau lttimeout(timeo ut)

i = 0
while i < 5:
try:
url = 'http://www.acme.com'
print url
req = urllib2.Request (url, None, headers)
response = urllib2.urlopen (req).read()
except:
#Never called :-/
print Timed-out."
if i == 4:
print "Exiting."
connection.clos e(True)
sys.exit()
else:
print "Trying again"
i = i + 1
time.sleep(10)
continue
=====

I haven't found a switch within urllib2 that would tell it to raise an
exception after it times out trying to download a web page. Any idea
how to have it stop trying after 5 tries?

Thank you.

[Steven D'Aprano]

Re: [urllib2] No time-out?

On Sun, 16 Nov 2008 12:04:02 +0100, Gilles Ganault wrote:

Hello
>
I'm using urllib2 to download web pages. The strange thing in the code
below, is that it seems like urllib2.urlopen retries indefinitely by
itself instead of raising an exception:

Try this instead (untested):

timeout = 30
socket.setdefau lttimeout(timeo ut)
url = 'http://www.acme.com'
for i in range(5):
try:
print url
req = urllib2.Request (url, None, headers)
response = urllib2.urlopen (req).read()
break
except urllib2.URLErro r:
print "Timed-out."
time.sleep(10)
else:
print "Exiting."
connection.clos e(True) # What is this?
sys.exit() # Do you really want the application to exit?



--
Steven