find() a larger string within a smaller string

[korean_dave]

stringa = "hi"
stringb = "hiyoooo"

I'd like it to return -1 when I do:

returnVal = stringa.find(st ringb);

Instead, it treats stringa as "hi" and stringb as "hi".

How do I solve this?

[Mensanator]

Re: find() a larger string within a smaller string

On Nov 14, 1:20 pm, korean_dave <davidrey...@gm ail.comwrote:

stringa = "hi"
stringb = "hiyoooo"
>
I'd like it to return -1 when I do:
>
returnVal = stringa.find(st ringb);
>
Instead, it treats stringa as "hi" and stringb as "hi".
>
How do I solve this?

Try this:

>>stringa = 'hi'
>>stringb = 'hiyoo'
>>stringa.find( stringb)

-1

[John Machin]

Re: find() a larger string within a smaller string

On Nov 15, 6:20 am, korean_dave <davidrey...@gm ail.comwrote:

stringa = "hi"
stringb = "hiyoooo"
>
I'd like it to return -1 when I do:
>
returnVal = stringa.find(st ringb);
>
Instead, it treats stringa as "hi" and stringb as "hi".

You appear to be gravely mistaken:

| >>stringa = "hi"
| >>stringb = "hiyoooo"
| >>returnVal = stringa.find(st ringb);
| >>returnVal
| -1

How do I solve this?

You need to tell us why you thought so; then, maybe, we can help.

[Gary Herron]

Re: find() a larger string within a smaller string

korean_dave wrote:

stringa = "hi"
stringb = "hiyoooo"
>
I'd like it to return -1 when I do:
>
returnVal = stringa.find(st ringb);
>
Instead, it treats stringa as "hi" and stringb as "hi".
>

No it doesn't. stringb is "hiyoooo" and it "treats" it that way.
(And just what do you mean by "treat"?)

How do I solve this?
>

There is nothing to solve. The expression

stringa.find(st ringb)

asks if "hi" contains "hiyoooo", and since it does not, it returns a -1 indicating so.

You'll have to describe what you expected and why you expected it before we will be able to see a problem that needs solving. (And then the problem will most likely be in your expectations, not in the find method.)


Gary Herron

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