En Fri, 19 Sep 2008 10:59:26 -0300, Ron Brennan <brennan.ron@gm ail.com>
escribió:
I guess you probably tried using ' '.join(value) and got an error like
this:
TypeError: sequence item 0: expected string, int found
so you inserted that str(...), but you don't still get what you want.
You want "145 2345 567 898". *If* you had a list like this: value =
["145", "2345", "567", "898"] (that is, a list of strings) *then* '
'.join(value) would do what you want. But you have this to start with
instead: value = [145, 2345, 567, 898] (a list of numbers), how to convert
it into a list of strings?
str(value) returns a single string that "looks like" a list but isn't:
"[145, 2345, 567, 898]". Instead, you need to convert each element
individually, and keep them in a list. Try this:
value = [str(elem) for elem in value]
Also, I'd use sorted() to iterate over all items. PUtting all together:
for tcKey, tcValue in sorted(dictiona ry.items()):
values = [str(elem) for elem in tcValue]
values = ' '.join(values)
print tcKey, values
or perhaps:
for tcKey, tcValue in sorted(find_a_g ood_name_for_me .iteritems()):
values_str = ' '.join(str(elem ) for elem in tcValue)
print tcKey, values_str
(using lazy objects (iteritems and a generator expression) instead of
concrete lists)
--
Gabriel Genellina
escribió:
Hello,
>
I have a multimap dictionary with a 1 Key to N values. I want to convert
the N values to a string to be used elsewhere in my program.
>
So I have dict[(1,[1, 2 ,3 ,4])] which I have sorted
>
When I do a print ''.join(str(dic t.value())) I get [1, 2, 3, 4] as an
output
when I really want 1 2 3 4
>
Here is my code:
>
dmapItems = dictionary.item s()
dmapItems.sort( )
>
for tcKey, tcValue in dmapItems:
file.write('Key = %s\nValue = %s" % (tcKey, tcValue)
>
stinger = ''.join(str(tcV alue))
>
print stringer
>
The Output = [145, 2345, 567, 898]
I need it to be 145 2345 567 898
>
I have a multimap dictionary with a 1 Key to N values. I want to convert
the N values to a string to be used elsewhere in my program.
>
So I have dict[(1,[1, 2 ,3 ,4])] which I have sorted
>
When I do a print ''.join(str(dic t.value())) I get [1, 2, 3, 4] as an
output
when I really want 1 2 3 4
>
Here is my code:
>
dmapItems = dictionary.item s()
dmapItems.sort( )
>
for tcKey, tcValue in dmapItems:
file.write('Key = %s\nValue = %s" % (tcKey, tcValue)
>
stinger = ''.join(str(tcV alue))
>
print stringer
>
The Output = [145, 2345, 567, 898]
I need it to be 145 2345 567 898
this:
TypeError: sequence item 0: expected string, int found
so you inserted that str(...), but you don't still get what you want.
You want "145 2345 567 898". *If* you had a list like this: value =
["145", "2345", "567", "898"] (that is, a list of strings) *then* '
'.join(value) would do what you want. But you have this to start with
instead: value = [145, 2345, 567, 898] (a list of numbers), how to convert
it into a list of strings?
str(value) returns a single string that "looks like" a list but isn't:
"[145, 2345, 567, 898]". Instead, you need to convert each element
individually, and keep them in a list. Try this:
value = [str(elem) for elem in value]
Also, I'd use sorted() to iterate over all items. PUtting all together:
for tcKey, tcValue in sorted(dictiona ry.items()):
values = [str(elem) for elem in tcValue]
values = ' '.join(values)
print tcKey, values
or perhaps:
for tcKey, tcValue in sorted(find_a_g ood_name_for_me .iteritems()):
values_str = ' '.join(str(elem ) for elem in tcValue)
print tcKey, values_str
(using lazy objects (iteritems and a generator expression) instead of
concrete lists)
--
Gabriel Genellina