find and replace with regular expressions

[chrispoliquin@gmail.com]

I am using regular expressions to search a string (always full
sentences, maybe more than one sentence) for common abbreviations and
remove the periods. I need to break the string into different
sentences but split('.') doesn't solve the whole problem because of
possible periods in the middle of a sentence.

So I have...

----------------

import re

middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')

# this will find abbreviations like e.g. or i.e. in the middle of a
sentence.
# then I want to remove the periods.

----------------

I want to keep the ie or eg but just take out the periods. Any
ideas? Of course newString = middle_abbr.sub ('',txt) where txt is the
string will take out the entire abbreviation with the alphanumeric
characters included.

[Mensanator]

Re: find and replace with regular expressions

On Jul 31, 3:07 pm, chrispoliq...@g mail.com wrote:

I am using regular expressions to search a string (always full
sentences, maybe more than one sentence) for common abbreviations and
remove the periods.  I need to break the string into different
sentences but split('.') doesn't solve the whole problem because of
possible periods in the middle of a sentence.
>
So I have...
>
----------------
>
import re
>
middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')
>
# this will find abbreviations like e.g. or i.e. in the middle of a
sentence.
# then I want to remove the periods.
>
----------------
>
I want to keep the ie or eg but just take out the periods.  Any
ideas?  Of course newString = middle_abbr.sub ('',txt) where txt is the
string will take out the entire abbreviation with the alphanumeric
characters included.

>>middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')
>>s = 'A test, i.e., an example.'
>>a = middle_abbr.sea rch(s) # find the abbreviation
>>b = re.compile('\.' ) # period pattern
>>c = b.sub('',a.grou p(0)) # remove periods from abbreviation
>>d = middle_abbr.sub (c,s) # substitute new abbr for old
>>d

'A test, ie, an example.'

[Mensanator]

Re: find and replace with regular expressions

On Jul 31, 3:56 pm, Mensanator <mensana...@aol .comwrote:

On Jul 31, 3:07 pm, chrispoliq...@g mail.com wrote:
>
>
>
>
>

I am using regular expressions to search a string (always full
sentences, maybe more than one sentence) for common abbreviations and
remove the periods.  I need to break the string into different
sentences but split('.') doesn't solve the whole problem because of
possible periods in the middle of a sentence.

>

So I have...

>

----------------

>

import re

>

middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')

>

# this will find abbreviations like e.g. or i.e. in the middle of a
sentence.
# then I want to remove the periods.

>

----------------

>

I want to keep the ie or eg but just take out the periods.  Any
ideas?  Of course newString = middle_abbr.sub ('',txt) where txt is the
string will take out the entire abbreviation with the alphanumeric
characters included.

>middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')
>s = 'A test, i.e., an example.'
>a = middle_abbr.sea rch(s)      # find the abbreviation
>b = re.compile('\.' )           # period pattern
>c = b.sub('',a.grou p(0))       # remove periods from abbreviation
>d = middle_abbr.sub (c,s)       # substitute new abbr for old
>d

>
'A test, ie, an example.'

A more versatile version:

import re

middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')
s = 'A test, i.e., an example.'
a = middle_abbr.sea rch(s) # find the abbreviation
b = re.compile('\.' ) # period pattern
c = b.sub('',a.grou p(0)) # remove periods from abbreviation
d = middle_abbr.sub (c,s) # substitute new abbr for old

print d
print
print

s = """A test, i.e., an example.
Yet another test, i.e., example with 2 abbr."""

a = middle_abbr.sea rch(s) # find the abbreviation
c = b.sub('',a.grou p(0)) # remove periods from abbreviation
d = middle_abbr.sub (c,s) # substitute new abbr for old

print d
print
print

s = """A test, i.e., an example.
Yet another test, i.e., example with 2 abbr.
A multi-test, e.g., one with different abbr."""

done = False

while not done:
a = middle_abbr.sea rch(s) # find the abbreviation
if a:
c = b.sub('',a.grou p(0)) # remove periods from abbreviation
s = middle_abbr.sub (c,s,1) # substitute new abbr for old ONCE
else: # repeat until all removed
done = True

print s

## A test, ie, an example.
##
##
## A test, ie, an example.
## Yet another test, ie, example with 2 abbr.'
##
##
## A test, ie, an example.
## Yet another test, ie, example with 2 abbr.
## A multi-test, eg, one with different abbr.

[Paul McGuire]

Re: find and replace with regular expressions

On Jul 31, 3:07 pm, chrispoliq...@g mail.com wrote:

>
middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')
>

When defining re's with string literals, it is good practice to use
the raw string literal format (precede with an 'r'):
middle_abbr = re.compile(r'[A-Za-z0-9]\.[A-Za-z0-9]\.')

What abbreviations have numeric digits in them?

I hope your input string doesn't include something like this:
For a good approximation of pi, use 3.1.

-- Paul

[MRAB]

Re: find and replace with regular expressions

On Jul 31, 9:07 pm, chrispoliq...@g mail.com wrote:

I am using regular expressions to search a string (always full
sentences, maybe more than one sentence) for common abbreviations and
remove the periods.  I need to break the string into different
sentences but split('.') doesn't solve the whole problem because of
possible periods in the middle of a sentence.
>
So I have...
>
----------------
>
import re
>
middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')
>
# this will find abbreviations like e.g. or i.e. in the middle of a
sentence.
# then I want to remove the periods.
>
----------------
>
I want to keep the ie or eg but just take out the periods.  Any
ideas?  Of course newString = middle_abbr.sub ('',txt) where txt is the
string will take out the entire abbreviation with the alphanumeric
characters included.

It's recommended that you should use a raw strings for regular
expressions.

Capture the letters using parentheses:

middle_abbr = re.compile(r'([A-Za-z0-9])\.([A-Za-z0-9])\.')

and replace what was found with what was captured:

newString = middle_abbr.sub (r'\1\2', txt)

HTH

[dusans]

Re: find and replace with regular expressions

On Jul 31, 10:07 pm, chrispoliq...@g mail.com wrote:

I am using regular expressions to search a string (always full
sentences, maybe more than one sentence) for common abbreviations and
remove the periods.  I need to break the string into different
sentences but split('.') doesn't solve the whole problem because of
possible periods in the middle of a sentence.
>
So I have...
>
----------------
>
import re
>
middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')
>
# this will find abbreviations like e.g. or i.e. in the middle of a
sentence.
# then I want to remove the periods.
>
----------------
>
I want to keep the ie or eg but just take out the periods.  Any
ideas?  Of course newString = middle_abbr.sub ('',txt) where txt is the
string will take out the entire abbreviation with the alphanumeric
characters included.

Its impossible with regex. U could try it with a statistical analysis;
and even this would give u a good split.

[dusans]

Re: find and replace with regular expressions

On Aug 1, 12:53 pm, dusans <dusan.smit...@ gmail.comwrote:

On Jul 31, 10:07 pm, chrispoliq...@g mail.com wrote:
>
>
>
>
>

I am using regular expressions to search a string (always full
sentences, maybe more than one sentence) for common abbreviations and
remove the periods.  I need to break the string into different
sentences but split('.') doesn't solve the whole problem because of
possible periods in the middle of a sentence.

>

So I have...

>

----------------

>

import re

>

middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')

>

# this will find abbreviations like e.g. or i.e. in the middle of a
sentence.
# then I want to remove the periods.

>

----------------

>

I want to keep the ie or eg but just take out the periods.  Any
ideas?  Of course newString = middle_abbr.sub ('',txt) where txt is the
string will take out the entire abbreviation with the alphanumeric
characters included.

>
Its impossible with regex. U could try it with a statistical analysis;
and even this would give u a good split.

"and even this wont* give u a good split." :P