simple problem with lists I am just forgetting

[Alexnb]

Lets say we have this list:

funlist = ['a', 'b', 'c']

and lets say I do this:

if funlist[4]:
print funlist[4]

I will get the exception "list index out of range"

How can I test if the list item is empty without getting that exception?
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[bearophileHUGS@lycos.com]

Re: simple problem with lists I am just forgetting

Alexnb:

How can I test if the list item is empty without getting that exception?

In Python such list cell isn't empty, it's absent. So you can use
len(somelist) to see how much long the list is before accessing its
items. Often you can iterate on the list with a for, so you don't need
to care of the len().

Bye,
bearophile

[Paul McGuire]

Re: simple problem with lists I am just forgetting

On Jul 31, 2:51 pm, Alexnb <alexnbr...@gma il.comwrote:

Lets say we have this list:
>
funlist = ['a', 'b', 'c']
>
and lets say I do this:
>
if funlist[4]:
    print funlist[4]
>
I will get the exception "list index out of range"
>
How can I test if the list item is empty without getting that exception?

Try using a slice. Slices are ignorant of list index validity.

funlist = list("abc") # too lazy to type ['a', 'b', 'c']
if funlist[4:]:
print funlist[4]

Voila! No exception!

-- Paul