How to subtract/add from/to a value found using the RE module?

[nihilium]

The beginning of the script goes like this.

[CODE=python]import urllib2
request = urllib2.urlopen ('http://ssd.jpl.nasa.go v/sbdb.cgi?sstr=2 000')
source= request.read()
import re
name = re.compile(r'si ze=\"\+1\"\>\<b \>(\d+) (\w+)')
thename = name.search(sou rce)[/CODE]

Now I want to subtract 1 from as well as add 1 to [CODE=python]thename.group(1 )[/CODE]

which always has a numerical value.

----

Another thing I don't get how to implement in regex, is how to match ranges such as 2001-3000. I tried using the following, which apparently did not work:

[CODE=python]list = re.compile(r'si ze=\"\+1\"\>\<b \>[2001-3000] \w+')[/CODE]

[bvdet]

The beginning of the script goes like this.

[CODE=python]import urllib2
request = urllib2.urlopen ('http://ssd.jpl.nasa.go v/sbdb.cgi?sstr=2 000')
source= request.read()
import re
name = re.compile(r'si ze=\"\+1\"\>\<b \>(\d+) (\w+)')
thename = name.search(sou rce)[/CODE]

Now I want to subtract 1 from as well as add 1 to [CODE=python]thename.group(1 )[/CODE]

which always has a numerical value.

----

Another thing I don't get how to implement in regex, is how to match ranges such as 2001-3000. I tried using the following, which apparently did not work:

[CODE=python]list = re.compile(r'si ze=\"\+1\"\>\<b \>[2001-3000] \w+')[/CODE]

This pattern will match a number in the range 2001-3000:[code=Python]re.compile(r'si ze=\"\+1\"\>\<b \>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')[/code][code=Python]
source = source.replace( thename.group(1 ),str(int(thena me.group(1))+1) )

patt = re.compile(r'si ze=\"\+1\"\>\<b \>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')
m = patt.search(sou rce)
print m.group(1)[/code]

[nihilium]

This pattern will match a number in the range 2001-3000:[code=Python]re.compile(r'si ze=\"\+1\"\>\<b \>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')[/code][code=Python]
source = source.replace( thename.group(1 ),str(int(thena me.group(1))+1) )

patt = re.compile(r'si ze=\"\+1\"\>\<b \>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')
m = patt.search(sou rce)
print m.group(1)[/code]

That works, thanks again. The range should look like this, though:

[CODE=Python]

re.compile(r'si ze=\"\+1\"\>\<b \>(2[0-9][0-9][1-9]|2[1-9][0-9][0-9]|2[0-9][1-9][0-9]|3000) \w+')
[/CODE]

as your solution did not match the range 2010-2099.

[bvdet]

That works, thanks again. The range should look like this, though:

[CODE=Python]

re.compile(r'si ze=\"\+1\"\>\<b \>(2[0-9][0-9][1-9]|2[1-9][0-9][0-9]|2[0-9][1-9][0-9]|3000) \w+')
[/CODE]

as your solution did not match the range 2010-2099.

Oops! Thanks for posting back and the correction.