comparing apache timestamps

[lihun]

I want to compare timestamps from an apache log file to see whether one request has been made less than five minutes after the previous one. Timestamp looks like this [05/Feb/2007:00:31:59 +0100]. How do I make the comparison?

[bvdet]

I want to compare timestamps from an apache log file to see whether one request has been made less than five minutes after the previous one. Timestamp looks like this [05/Feb/2007:00:31:59 +0100]. How do I make the comparison?

Does anyone have a better way?[code=Python]import time, datetime
def date_compare(ts 1, ts2, **compkw):
t1 = time.strptime(t s1.strip('[]').split()[0], '%d/%b/%Y:%H:%M:%S')
d1 = datetime.dateti me(*t1[:6])

t2 = time.strptime(t s2.strip('[]').split()[0], '%d/%b/%Y:%H:%M:%S')
d2 = datetime.dateti me(*t2[:6])

delta = d2-d1
orderList = ['days', 'hours', 'minutes', 'seconds']
outList = []
for item in orderList:
if compkw.has_key( item):
outList.append( '%s %s' % (compkw[item], item))
outStr = ', '.join(outList)

if delta <= datetime.timede lta(**compkw):
return 'Less than or equal to %s' % (outStr)
return 'Greater than %s' % (outStr)[/code]
Example:
[code=Python]
>>> ts1 = '[05/Feb/2007:00:31:59 +0100]'
>>> ts2 = '[09/Feb/2007:00:37:00 +0100]'
>>> print date_compare(ts 1, ts2, minutes=5, days=2)
Greater than 2 days, 5 minutes
>>> ts1 = '[05/Feb/2007:00:31:59 +0100]'
>>> ts2 = '[05/Feb/2007:00:36:59 +0100]'
>>> print date_compare(ts 1, ts2, minutes=5)
Less than or equal to 5 minutes
>>> [/code]