how to dynamically create a function object (from a code object)?

[Petri Savolainen]

After reading the manuals and googling around a bit, I thought I'd use
the 'compile' built-in to create a code object. Then, using either
new.function() or types.FunctionT ype(), create a function object out of
the code object. The function object can then be turned into a method
for example using types.MethodTyp e(). Right? Well, on Windows 98, using
python 2.2.2 (or 2.3b2):
[color=blue][color=green][color=darkred]
>>> c=compile('def a(msg): return msg','<nowhere> ','exec')
>>> f=types.Functio nType(c,globals (),'a')
>>> f
>>> <code object ? at 00F8A9E0, file "<nowhere>" , line 1>
>>> f('hello')[/color][/color][/color]

Traceback (most recent call last):
File "<pyshell#136>" , line 1, in -toplevel-
f('hello')
TypeError: ?() takes no arguments (1 given)
[color=blue][color=green][color=darkred]
>>> f()
>>>
>>> a('hello')
>>> 'hello'
>>>[/color][/color][/color]

This is, well, not what I would have expected.

After peeking around in the code object, I found out its 'co_const'
instance variable also contains a code object - which, it seems, should
really be fed to the function creation methods:
[color=blue][color=green][color=darkred]
>>> c.co_consts[/color][/color][/color]
(<code object a at 00F8A960, file "<nowhere>" , line 1>, None)[color=blue][color=green][color=darkred]
>>> f=types.Functio nType(c.co_cons ts[0],globals(),'a')
>>> f('hello')[/color][/color][/color]
'hello'[color=blue][color=green][color=darkred]
>>>[/color][/color][/color]

Which is the behaviour I would have expected in the first place!

I would really like to know what I am doing wrong here, or any
clarification regarding what is going on above... I dare not hope having
found a bug :-P

Thanks,

Petri