Regular Expressions

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  • Andy Jacobs
    #1

    Regular Expressions

    Hi all

    Hopefully a nice easy one :o)

    I've got a table with a list of 'installers'. I have a form for
    visitors to find an installer in their area searchning on post code.

    Let's say we have installers in:

    RG (Reading)
    G (Glasgow)

    The page tells the vistor to type in the first letter(s) of their post
    code. So, if a visitor types in their postcode as RG23 1TQ, it works.
    If they type in G23 1TQ then it doesn't. If they type in just G - as
    instructed - then it works.

    I've just chopped off all but the first 2 digits of whatever they type
    in (RG or G2). What I would like to do is (In pigeon PHP):

    If characters one and two are letters, use this for the search.

    If character one is a letter and character two is a number then just
    chop the first character off and use it for the search.

    elseif display error.

    What I can't get my head round is the logic and regular expressions
    behind this.

    Could someone throw me a lifeline please.

    Cheers

    Andy
    Tags: None
    • Mick White
      #2
      Re: Regular Expressions

      Andy Jacobs wrote:
      [color=blue]
      > Hi all
      >
      > Hopefully a nice easy one :o)
      >
      > I've got a table with a list of 'installers'. I have a form for
      > visitors to find an installer in their area searchning on post code.
      >
      > Let's say we have installers in:
      >
      > RG (Reading)
      > G (Glasgow)
      >
      > The page tells the vistor to type in the first letter(s) of their post
      > code. So, if a visitor types in their postcode as RG23 1TQ, it works.
      > If they type in G23 1TQ then it doesn't. If they type in just G - as
      > instructed - then it works.
      >
      > I've just chopped off all but the first 2 digits of whatever they type
      > in (RG or G2). What I would like to do is (In pigeon PHP):
      >
      > If characters one and two are letters, use this for the search.
      >
      > If character one is a letter and character two is a number then just
      > chop the first character off and use it for the search.
      >
      > elseif display error.
      >
      > What I can't get my head round is the logic and regular expressions
      > behind this.[/color]

      Grab the first 2 characters (if the entry is 2 or more characters)

      replace digit with "" (Nothing)

      Mick

        Comment

        • Michael Fesser
          #3
          Re: Regular Expressions

          .oO(Andy Jacobs)
          [color=blue]
          >I've just chopped off all but the first 2 digits of whatever they type
          >in (RG or G2). What I would like to do is (In pigeon PHP):
          >
          >If characters one and two are letters, use this for the search.
          >
          >If character one is a letter and character two is a number then just
          >chop the first character off and use it for the search.
          >
          >elseif display error.[/color]

          if (preg_match('#^[a-z]{1,2}#i', $yourString, $result)) {
          // use $result[0] for search
          } else {
          // error handling
          }

          Micha

            Comment

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