reading only the last number from i.e. "1234" (4 that will be)

**Michael Fesser** · Jul 17 '05, 10:46 AM

Re: reading only the last number from i.e. "1234&quot ; (4 that will be)

.oO(JaNE)
[color=blue]
>I have one language specific problem with my site. I would like to tell
>how meny pictures someone have in his or her gallery and I would like to
>have it properly speled (in Croatian). So, I don't want to write:
>"number of pitures in this gallery: 123" rather "John have 123
>pictures"... but, here is my problem, I will write now some little
>Croatian with differences in capital letters:
>[...]
>
>so that is pattern:
>all numbers which ends with 1 need to have "U",
>2-4 = "E"
>5-x0 = "A"
>
>and question: how to read only the last number from count(*) ?[/color]

I would do it differently. The pattern is always the same, so it's quite
easy to just devide the number by 10 and have a look at the remainder
(modulo operation), e.g.

$number = 22;
$foo = array('a', 'u', 'e', 'e', 'e', 'a', 'a', 'a', 'a', 'a');
print $foo[$number % 10];

will print 'e'.

The array $foo contains the chars for 0, 1, 2, ... , 9. The expression

$number % 10

calculates the remainder when deviding the number by 10, which is then
used as an index in the char array.

HTH
Micha

**Schraalhans Keukenmeester** · Jul 17 '05, 10:46 AM

Re: reading only the last number from i.e. "1234&quot ; (4 that will be)

JaNE wrote:[color=blue]
> as 1st, sorry on my clumsy english (now I realy miss some words)
>
> I have one language specific problem with my site. I would like to tell
> how meny pictures someone have in his or her gallery and I would like to
> have it properly speled (in Croatian). So, I don't want to write:
> "number of pitures in this gallery: 123" rather "John have 123
> pictures"... but, here is my problem, I will write now some little
> Croatian with differences in capital letters:
>
> 1 slikU
> 2 slikE
> 3 slikE
> 4 slikE
> 5 slikA
> 6 slikA
> 7 slikA
> ...
> 20 slikA
> 21 slikU
> 22 slikE
> 23 slikE
> 24 slikE
> 25 sliKA
> ...
> 99 slikA
> 100 slikA
> 101 slikU
> 102 slikE...
>
> so that is pattern:
> all numbers which ends with 1 need to have "U",
> 2-4 = "E"
> 5-x0 = "A"
>
> and question: how to read only the last number from count(*) ?
>[/color]
You could also do a typeconversion:

$str = (string) $num;
$lastchar = $str [strlen($str)-1];

followed by an if/else or a switch/case statement, or a lookup using the
reconverted char in a predefined string/array with all the appropriate
characters/strings.

You may omit the explicit conversion, but it is not good coding practice.

Using modulo as offered by others is probably the neater, quicker and
more correct approach I admit. The latter bit (the lookup) can be used
in the modulo approach very well too.

Schraalhans.

**Chung Leong** · Jul 17 '05, 10:46 AM

Re: reading only the last number from i.e. "1234&quot ; (4 that will be)

"JaNE" <not_me@mail.do t> wrote in message
news:1gqjgxv.1j lgn2h13rc8wqN%n ot_me@mail.dot. ..[color=blue]
> as 1st, sorry on my clumsy english (now I realy miss some words)
>
> I have one language specific problem with my site. I would like to tell
> how meny pictures someone have in his or her gallery and I would like to
> have it properly speled (in Croatian). So, I don't want to write:
> "number of pitures in this gallery: 123" rather "John have 123
> pictures"... but, here is my problem, I will write now some little
> Croatian with differences in capital letters:[/color]

Use the % operator to get the remainder after a division:

5 % 10 == 5
15 % 10 == 5
135 % 10 == 5
1234 % 10 == 4

For the word endings, you probably want to write a function since the logic
can get quite complicated. And it's something you'd use often.

An example:

function k($num) {
if($num >= 10 && $num <= 19) {
return 'a';
}
$mod = $num % 10;
if($mod == 1) {
return 'u';
}
else if($mod >= 5) {
return 'a';
}
else {
return 'e';
}
}

I'm guessing here that it's "0 slika" and not "0 sliku".

For those who don't understand what the problem is: the OP wants to print
the correct word ending for a given number of objects. In English, we have
"1 picture" but "2 pictures". In Slavic languages this is much more
complicated. 1 is singular; 2, 3, and 4 are plural; 5 and above need a
different declension (4 pictures, but 5 of pictures). The final digit
determines the ending (24 pictures, 25 of pictures), which is why the
modulus of 10 is taken. The exceptions are 10 - 19.

**R. Rajesh Jeba Anbiah** · Jul 17 '05, 10:47 AM

[OT] Re: reading only the last number from i.e. "1234&quot ; (4 that will be)

Chung Leong wrote:
<snip>[color=blue]
> I'm guessing here that it's "0 slika" and not "0 sliku".
>
> For those who don't understand what the problem is: the OP wants to[/color]
print[color=blue]
> the correct word ending for a given number of objects. In English, we[/color]
have[color=blue]
> "1 picture" but "2 pictures". In Slavic languages this is much more
> complicated. 1 is singular; 2, 3, and 4 are plural; 5 and above need[/color]
a[color=blue]
> different declension (4 pictures, but 5 of pictures). The final digit
> determines the ending (24 pictures, 25 of pictures), which is why the
> modulus of 10 is taken. The exceptions are 10 - 19.[/color]

Oh cool:) Chung knows Croatian too...

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reading only the last number from i.e. "1234" (4 that will be)

reading only the last number from i.e. "1234" (4 that will be)

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