how to use the keyword 'static' in PHP 4?

[lkrubner@geocities.com]

In the code below I'm getting a parse error on this line:

static $controllerForA ll = new McControllerFor All();

why does this give me a parse error? I'm running PHP 4.



function & getController($ callingCode=fal se) {
// 11-27-04 - we want to get the controllerForAl l variable, and we
want to make
// sure that it is always passed by reference. Rather than having
functions do
// something like this:
//
// global $controllerForA ll;
//
// we instead want them to use this function. This adds a wrapper to
the way we
// this variable and thus allows more flexibility in changing the
access later.
// After all, it may not remain in global space in future versions of
the
// software.

// 12-12-04 - we declare controllerForAl l to be static, therefore the
second time
// this function is called it should already exist.

if (is_object($con trollerForAll)) {
if ($callingCode) $controllerForA ll->setCallingCode ($callingCode);
return $controllerForA ll;
} else {
$controllerForA ll = & $GLOBALS["controllerForA ll"];
if (is_object($con trollerForAll)) {
if ($callingCode) $controllerForA ll->setCallingCode ($callingCode);
return $controllerForA ll;
} else {
if (class_exists(" McControllerFor All")) {
static $controllerForA ll = new McControllerFor All();
if (is_object($con trollerForAll)) {
if ($callingCode) $controllerForA ll->setCallingCode ($callingCode);

return $controllerForA ll;
} else {
echo "Awful sorry, we were looking for a software object called
'McControllerFo rAll' but we were unable to find it. The software
really, really needs it to work.";
}
} else {
echo "Awful sorry, we were looking for a software object called
'McControllerFo rAll' but we were unable to find it. The software
really, really needs it to work.";
}
}
}
}

[Norman Peelman]

Re: how to use the keyword 'static' in PHP 4?

<lkrubner@geoci ties.com> wrote in message
news:1103190614 .611168.14090@z 14g2000cwz.goog legroups.com...[color=blue]
> In the code below I'm getting a parse error on this line:
>
> static $controllerForA ll = new McControllerFor All();
>
> why does this give me a parse error? I'm running PHP 4.
>
>
>
> function & getController($ callingCode=fal se) {
> // 11-27-04 - we want to get the controllerForAl l variable, and we
> want to make
> // sure that it is always passed by reference. Rather than having
> functions do
> // something like this:
> //
> // global $controllerForA ll;
> //
> // we instead want them to use this function. This adds a wrapper to
> the way we
> // this variable and thus allows more flexibility in changing the
> access later.
> // After all, it may not remain in global space in future versions of
> the
> // software.
>
> // 12-12-04 - we declare controllerForAl l to be static, therefore the
> second time
> // this function is called it should already exist.
>
> if (is_object($con trollerForAll)) {
> if ($callingCode) $controllerForA ll->setCallingCode ($callingCode);
> return $controllerForA ll;
> } else {
> $controllerForA ll = & $GLOBALS["controllerForA ll"];
> if (is_object($con trollerForAll)) {
> if ($callingCode) $controllerForA ll->setCallingCode ($callingCode);
> return $controllerForA ll;
> } else {
> if (class_exists(" McControllerFor All")) {
> static $controllerForA ll = new McControllerFor All();
> if (is_object($con trollerForAll)) {
> if ($callingCode) $controllerForA ll->setCallingCode ($callingCode);
>
> return $controllerForA ll;
> } else {
> echo "Awful sorry, we were looking for a software object called
> 'McControllerFo rAll' but we were unable to find it. The software
> really, really needs it to work.";
> }
> } else {
> echo "Awful sorry, we were looking for a software object called
> 'McControllerFo rAll' but we were unable to find it. The software
> really, really needs it to work.";
> }
> }
> }
> }
>[/color]

I believe that 'static' can only be used for non-computed values... so:

static $var = 1; // is ok
static $var = 1+1; // not ok

try this:

if (class_exists(" McControllerFor All")) {
$tmp = new McControllerFor All();
static $controllerForA ll = $tmp;
}


Check out this link...

http://us2.php.net/manual/en/language.variables.scope.php

Norm
---
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[Janwillem Borleffs]

Re: how to use the keyword 'static' in PHP 4?

Norman Peelman wrote:[color=blue]
> <lkrubner@geoci ties.com> wrote in message
> news:1103190614 .611168.14090@z 14g2000cwz.goog legroups.com...[color=green]
>> In the code below I'm getting a parse error on this line:
>>
>> static $controllerForA ll = new McControllerFor All();
>>
>> why does this give me a parse error? I'm running PHP 4.
>>[/color][/color]

You will have to do it in two steps:

static $controllerForA ll ;
$controllerForA ll = new McControllerFor All();


JW

[lkrubner@geocities.com]

Re: how to use the keyword 'static' in PHP 4?

Thanks. I seemed to have solved the problem by moving this line to the
top of the function:

static $controllerForA ll;
I guess it only runs the first time the function is called.