Use <div> in php page

[ghjk]

I'm using php,mysql,ajax in my web application. my index.php page has search option. I want the results to display different page(stock.php) but not in index page. When I use <div> in index page it works. But when I put div in different page it doesn't work. Where I goes wrong? Please help me..
This is my code.
index.php

<tr>[LEFT]
              <td  height="30">&nbsp;Year&nbsp;&nbsp;&nbsp;:</td>
              <td><? getVehicleYear(); ?></td>
            </tr>
            <tr>
              <td  height="30">&nbsp;Fuel&nbsp;&nbsp;&nbsp;&nbsp;:</td>
              <td><? getVehicleFuel();?> </td>
            </tr>
			<tr><td colspan="2"align="right">
			<input type="image" src="http://bytes.com/images/searchBtn.jpg"  name="Search" id="Search" onclick=" searchVehicle(); return false;" />
		[/LEFT]

Ajax code

[LEFT]function searchVehicle(){
		

	var dropdownIndex = document.getElementById('Year').selectedIndex;
	var year = document.getElementById('Year')[dropdownIndex].value;
	
	var dropdownIndex = document.getElementById('Fuel').selectedIndex;
	var fuel = document.getElementById('Fuel')[dropdownIndex].value;
	

	
				
	var request = GetXmlHttpObject();
	var url="searchResult.php";
	url=url+"?year="+year+"&fuel="+fuel+"&S="+1;


	url=url+"&sid="+Math.random();
	request.onreadystatechange=stateChanged;
	request.open("GET",url,true);
	
	request.send(null);

	function stateChanged()
   {
	 if (request.readyState==4)  
		{
			
			document.getElementById("t").innerHTML=request.responseText;
			
		}
 	}
}[/LEFT]

searchResult.ph p

[LEFT]if($_GET['S']==1){

	$year=$_GET['year'];
	$fuel=$_GET['fuel'];

	
		$sql="SELECT * FROM vehicles WHERE year='$year' AND fuel='fuel'";
		$result = mysql_query($sql)or die(mysql_error());

		echo "<table width=100% align=center>";
	echo "&nbsp;&nbsp;<tr height=20 bgcolor=#C0C0C0><td align=center>Year</td><td align=center>Fuel</td><td>SELECT</td></tr>";

	while($row = mysql_fetch_array($result))
	{
		foreach( $row AS $key => $val ){
		$$key = stripslashes( $val );
		}
			
	echo "<tr class=normalText>";
 
	echo "<td> $year</td>";
	echo "<td> $fuel</td>";
	

	echo  "<td><a href='javascript:void(0);' onclick=\"LookupVehicle('$year','$fuel'); return false;\">Select</a></td>";
			echo "</tr>";
	}
	echo "</table>";
	
	}[/LEFT]

stock.php

<div id="t"></div>

[johny10151981]

Javascript locate object only in the current page. It does not look for a object in different page. With some exception. your div object with ID T is in different object.

I am not sure what are you trying to achieve, I didn't even tried to read. But If you want to change the entire page use

document.location='stock.php?data1=data&data2=data&data3=data'

But if you dont want to use get method. try different approaches

but you must remember your Javascript wont get object if it does not exists in your current page. and an object can be created or loaded using javascript from server

[ghjk]

Thank you johny10151981. Your code is working. Actually In my web application 3 or more pages having same search function. But I want to display search results in one page not in own page.When user search 1st page; search results will displays on result page. 2nd page also results should be on results page. Using your code it goes to the results page . But I couldn't get results. Please help me...
ajax code

    function searchVehicle(){
     
     
        var dropdownIndex = document.getElementById('Year').selectedIndex;
        var year = document.getElementById('Year')[dropdownIndex].value;
     
        var dropdownIndex = document.getElementById('Fuel').selectedIndex;
        var fuel = document.getElementById('Fuel')[dropdownIndex].value;
     
     
     
     
        var request = GetXmlHttpObject();
        var url="searchResult.php";
        url=url+"?year="+year+"&fuel="+fuel+"&S="+1;
     
     
        url=url+"&sid="+Math.random();
        request.onreadystatechange=stateChanged;
        request.open("GET",url,true);
     
        request.send(null);
     
        function stateChanged()
       {
         if (request.readyState==4)  
            {
     
document.location='stock.php?year=year&fuel=fuel';
     
            }
         }
    }

This code in my stock.php page

if($_GET['S']==1){

	$year=$_GET['year'];
	$fuel=$_GET['fuel'];
echo $year;
}