Extract the URL of a RSS feed from source code with Regex

[emnia]

Can anybody help me with this questions? It's probably easy for you...

Example:

<link rel="alternate" type="application/rss+xml" title="RSS 2.0" href="http://site.com/feed.rss" />

I need the href value from that string. I tried many Regex examples but they did not work so good.

Any hints would be welcome!

[Atli]

Hi.

I would think something like this would work:
[code=php]
$success = preg_match('/\<link.*href=\" (.*)\" \/\>/is', $str, $matches);
[/code]
To break that down, we have the opening "<link", followed by any number of any character, until it reaches a href=", from which point we want any number of any characters, until we reach the closing ", followed by the closing />

[emnia]

Thanks! It worked great!

Thanks to you I can now improve my site thanks!
I used it on a link directory site for Kazakh sites, yeah right, (www.REMOVED-BY.MOD.) to grab the RSS url if the user forgot to enter it.

This will help many others I think!

PS. My function looks like this now:

[PHP]function grab_rss_url($u rl){

$text = @file_get_conte nts($url);
$text = substr($text,0, 3000);

$success = preg_match('/\<link.*href=\" (.*)\" \/\>/is', $text, $matches);

return $matches[1];

}[/PHP]