Using URL in opendir() as absolute path

[kkhan5000]

Hello,

I would like to use an URL insttead of a local path in the following command, is it possible?

[CODE=php]
$url = 'http://www.mysite.com/content/';
$dir = opendir($url);
[/CODE]

Thank you,

kkhan

[chazzy69]

I don't know about that function but you can use fopen to open a file with a url, also you mabye be able to use an include statement depending on what your trying to achieve.

[kkhan5000]

Thank you chazzy69. Here is the php code I am working. This lists and display files from a certain folder. I would like to use this code as an include for several directories, however, it always want to look for $dirpath below the current folder. I hope that a fixed url will fix this problem, but I am not sure whether opendir function can use urls instead of local paths.

[code=php]
<?php
$dirpath = "content";
$dh = opendir($dirpat h);
while (false !== ($file = readdir($dh))) {
$fileList[] = trim($file);

//Don't list subdirectories
if (!is_dir("$dirp ath/$file")){
sort ($fileList); // sort the file list in the array
}
}
reset ($fileList); // go back to the top of the array
while (list ($key, $file) = each ($fileList))
{
//Truncate the file extension and capitalize the first letter
echo "<a href='$dirpath/$file'>". htmlspecialchar s(ucfirst(preg_ replace('/\..*$/', '', $file))). "<br />";"</a>";


}
closedir($dh);
?>
[/code]