Nested foreach loop over same array

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  • Ivan S
    #1

    Nested foreach loop over same array

    I'm using next snippet:

    $somearray = array(...);

    foreach($somear ray as $item1) {
    foreach($item1 as $item2) {
    // ... do something ...
    }
    }

    ....and I'm getting next error:
    Invalid argument supplied for foreach()

    on second foreach.

    This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
    but site seems to work ok.


    Is there any way to avoid that error?


    Tnx.
    Tags: None
    • Erwin Moller
      #2
      Re: Nested foreach loop over same array


      Ivan S schreef:
      I'm using next snippet:
      >
      $somearray = array(...);
      >
      foreach($somear ray as $item1) {
      foreach($item1 as $item2) {
      // ... do something ...
      }
      }
      >
      ...and I'm getting next error:
      Invalid argument supplied for foreach()
      >
      on second foreach.
      Hi Ivan,

      Nothing wrong with your code.
      The two foreach constructs should be no problem.
      I expect that the original array isn't containing what you expect it to
      contain.
      Since you use a foreach on every value in the $somearray, this array
      should contain of arrays itself.

      Test that like this:
      echo "<pre>";
      print_r($somear ray);
      echo "</pre>";
      exit;

      Regards,
      Erwin Moller



      >
      This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
      but site seems to work ok.
      >
      >
      Is there any way to avoid that error?
      >
      >
      Tnx.

        Comment

        • Olaf Schinkel
          #3
          Re: Nested foreach loop over same array

          Ivan S schrieb:
          I'm using next snippet:
          >
          $somearray = array(...);
          >
          foreach($somear ray as $item1) {
          foreach($item1 as $item2) {
          // ... do something ...
          }
          }
          >
          ...and I'm getting next error:
          Invalid argument supplied for foreach()
          >
          on second foreach.
          >
          This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
          but site seems to work ok.
          >
          >
          Is there any way to avoid that error?
          >
          >
          Tnx.
          The function is_array() exists :-)

            Comment

            • Ivan S
              #4
              Re: Nested foreach loop over same array

              On 9 srp, 12:06, Erwin Moller
              <Since_humans_r ead_this_I_am_s pammed_too_m... @spamyourself.c omwrote:
              Ivan S schreef:
              >
              I'm using next snippet:
              >
              $somearray = array(...);
              >
              foreach($somear ray as $item1) {
                    foreach($item1 as $item2) {
                          // ... do something ...
                   }
              }
              >
              ...and I'm getting next error:
              Invalid argument supplied for foreach()
              >
              on second foreach.
              >
              Hi Ivan,
              >
              Nothing wrong with your code.
              The two foreach constructs should be no problem.
              I expect that the original array isn't containing what you expect it to
              contain.
              Since you use a foreach on every value in the $somearray, this array
              should contain of arrays itself.
              >
              Test that like  this:
              echo "<pre>";
              print_r($somear ray);
              echo "</pre>";
              exit;
              >
              Regards,
              Erwin Moller
              >
              >
              >
              This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
              but site seems to work ok.
              >
              Is there any way to avoid that error?
              >
              Tnx.
              >
              >
              Hi Erwin. :)

              Your advice helped, some items in $somearray weren't arrays it self,
              that was reason why i got errors reported.

              Thanks for your help.

                Comment

                • Ivan S
                  #5
                  Re: Nested foreach loop over same array

                  On 10 srp, 05:25, Olaf Schinkel <tr...@schinkel .tvwrote:
                  Ivan S schrieb:
                  >
                  I'm using next snippet:
                  >
                  $somearray = array(...);
                  >
                  foreach($somear ray as $item1) {
                        foreach($item1 as $item2) {
                              // ... do something ...
                       }
                  }
                  >
                  ...and I'm getting next error:
                  Invalid argument supplied for foreach()
                  >
                  on second foreach.
                  >
                  This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
                  but site seems to work ok.
                  >
                  Is there any way to avoid that error?
                  >
                  Tnx.
                  >
                  The function is_array() exists :-)
                  I know that...I wasn't aware that my input array could contain
                  unexpected values (such as non array values).

                    Comment

                    • Barry
                      #6
                      Re: Nested foreach loop over same array


                      "Ivan S" <ivan.skugor@gm ail.comwrote in message
                      news:f0ebdfc4-5660-4d1d-accb-b35f0946d9ff@i7 6g2000hsf.googl egroups.com...
                      On 10 srp, 05:25, Olaf Schinkel <tr...@schinkel .tvwrote:
                      Ivan S schrieb:
                      >
                      I'm using next snippet:
                      >
                      $somearray = array(...);
                      >
                      foreach($somear ray as $item1) {
                      foreach($item1 as $item2) {
                      // ... do something ...
                      }
                      }
                      >
                      ...and I'm getting next error:
                      Invalid argument supplied for foreach()
                      >
                      on second foreach.
                      >
                      This works on PHP 5, but on PHP 4 I get that error (in Apache logs),
                      but site seems to work ok.
                      >
                      Is there any way to avoid that error?
                      >
                      Tnx.
                      >
                      The function is_array() exists :-)
                      I know that...I wasn't aware that my input array could contain
                      unexpected values (such as non array values).


                      =========

                      strictly speaking, avoid the error like this:

                      $somearray = array(...);
                      foreach ($somearray as $item1)
                      {
                      if (!is_array($ite m1)){ $item1 = array($item1); }
                      foreach ($item1 as $item2)
                      {
                      // do something...
                      }
                      }

                      that way, if $item1 is not an array but still a usable, otherwise valid,
                      value then your next foreach will be able to process it normally...base d on
                      whatever '...do something...' is.


                        Comment

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